Two dimensional Elastic Collision

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The discussion revolves around solving a two-dimensional elastic collision problem involving a helium atom and an oxygen atom. The helium atom, moving at 240 m/s, collides with the stationary oxygen atom, which is four times more massive. The conservation of momentum and energy principles are applied to derive equations for the final velocities of both atoms. Participants suggest simplifying the problem by using components for the velocities, which aids in solving the equations without needing the angle of deflection. The conversation highlights the importance of breaking down the vectors to find the magnitudes of the final velocities effectively.
CalebB-M
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Homework Statement

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The problem statement is: A helium atom traveling at a speed of 240 m/s hits an oxygen atom at rest. If the helium atom rebounds elastically, from the oxygen atom at an angle of 90° with respect to the original direction of motion, what are the final velocities of both atoms. (hint the oxygen is approximately 4 times as massive as the helium.)

Homework Equations


I understand that Momentum is conserved Pi = Pf thus m*v1i + m*v2i = m*v1f + m*v2f
Energy is also conserved in an elastic collision.
1/2m * v^2 = ke

The Attempt at a Solution


I can setup the coordinate system with +x being the initial direction of the helium particle. I also tried writing it in vector notation. my initial setup looked like this
M*[ 240x, 0y, 0z] + 0 (because it is at rest) = M*[0x,sin90*|v1f|y, 0z] + 4M*[cos♤*|v2f|x,sin♤*|v2f|y, 0z]
With ♤ being the unknown direction.
I also attempted to find the magnitude of the velocities by CE, I found that 1/2 M *(240)^2 = 1/2M*(v1f)^2 + 2M*(v2f)^2. Canceling out the mass I found that 240^2 = v1f^2 /2 + 2*v2f^2. I am lost on the next step.
Any direction would be helpful thank you!
 
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Hello. You have the correct approach. I think it's easier to do the algebra if you write the components of the velocity as v2x rather than v2⋅cosθ, etc. Thus, get equations for v1y, v2x, and v2y.
 
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Ahhhh I see it now haha, by substituting V2x for cos♤*V2 and V2y for sin♤*V2 I can find the magnitudes without knowing the theta then I can plug an chug the systems of equations. Thanks!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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