Two Hanging mass's attached to one on the table

  • Thread starter charan1
  • Start date
  • #1
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Homework Statement


The coefficient of kinetic friction between the 2.0 kg block in figure and the table is 0.350.

What is the acceleration of the 2.0 kg block?

Homework Equations


F=uK*Force Normal
Fnet=ma

The Attempt at a Solution


I tried to take the mass's of both the hanging and used them to calculate a net force on the block in the center and then solved for acceleration that way. Here's my work.

3kg*9.8=29.4N Right Side Tension
1kg*9.8=9.8N Left Side Tension
2kg*9.8=19.6N Force Normal

F=.35*19.6N
6.86N

(29.4N-6.86N)-9.8N=2kg*acceleration

a=6.34m/s^2

and it turns out this is wrong please help me out thank you!

-Charan
 

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Answers and Replies

  • #2
nasu
Gold Member
3,769
428
You forgot the left side tension....
 

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