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Homework Statement
The coefficient of kinetic friction between the 2.0 kg block in figure and the table is 0.350.
What is the acceleration of the 2.0 kg block?
Homework Equations
F=uK*Force Normal
Fnet=ma
The Attempt at a Solution
I tried to take the mass's of both the hanging and used them to calculate a net force on the block in the center and then solved for acceleration that way. Here's my work.
3kg*9.8=29.4N Right Side Tension
1kg*9.8=9.8N Left Side Tension
2kg*9.8=19.6N Force Normal
F=.35*19.6N
6.86N
(29.4N6.86N)9.8N=2kg*acceleration
a=6.34m/s^2
and it turns out this is wrong please help me out thank you!
Charan
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