(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The coefficient of kinetic friction between the 2.0 kg block in figure and the table is 0.350.

What is the acceleration of the 2.0 kg block?

2. Relevant equations

F=uK*Force Normal

Fnet=ma

3. The attempt at a solution

I tried to take the mass's of both the hanging and used them to calculate a net force on the block in the center and then solved for acceleration that way. Here's my work.

3kg*9.8=29.4N Right Side Tension

1kg*9.8=9.8N Left Side Tension

2kg*9.8=19.6N Force Normal

F=.35*19.6N

6.86N

(29.4N-6.86N)-9.8N=2kg*acceleration

a=6.34m/s^2

and it turns out this is wrong please help me out thank you!

-Charan

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# Homework Help: Two Hanging mass's attached to one on the table

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