Two Ice Skaters Force On Each Other

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Two ice skaters of equal mass are spinning in a circle, completing one rotation every 2.4 seconds, with arms 0.75 m long and each weighing 56.0 kg. The initial approach using the gravitational force equation was incorrect for this scenario. Instead, the appropriate method involves applying the centripetal force formula, F=ma, where 'a' represents the centripetal acceleration. The discussion emphasizes the importance of using the correct physics principles to solve for the force they exert on each other. Clarification on the use of time in the calculations is also noted as essential for determining the correct force.
thulling
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1. On an ice rink, two skaters of equal mass grab hands and spin in a mutual circle once every 2.4 s.
If we assume their arms are each 0.75 m long and their individual masses are 56.0 kg, how hard are they pulling on one another? (answer is F= __N)



2. I thought I should use the equation F= G((M one)(M two))/radius squared
where G=6.67*10^-11 N*(m/kg)squared

3. I attempted to plug in the numbers to this equation and got F=3.7*10^-7
This answer was incorrect.

I know I am given time=2.4s, but I am not sure where to use this. ?

Please help
 
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That equation you used was for the force of gravity between the skaters. It's not significant here. Try to use F=ma
 
I got it! Thanks so much!
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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