1. The problem statement, all variables and given/known data Two in-phase loudspeakers emit identical 1000 Hz sound waves along the x-axis. What distance should one speaker be placed behind the other for the sound to have an amplitude 1.60 times that of each speaker alone? 2. Relevant equations None given, but I assume: v=f[tex]\lambda[/tex] A = 2asin(kx) 3. The attempt at a solution 1.6a = 2asin(kx) Found k=(2pi)/wavelength = (2pi/0.343) using v = 343 m/s arcsin(0.8)=18.318x x = 0.0506m But this answer is wrong. Help?