- #1

- 20

- 5

**I solved it, but then saw another solution online and am wondering if is is correct (since it is much faster than mine) and if my reasoning of it is correct**

1. Homework Statement

1. Homework Statement

Two loudspeakers emit sound waves along the x-axis. A listener in front of both speakers hears a maximum sound intensity when speaker 2 (s

_{2}) at origin and speaker 1 (S

_{1}) at x = 0.50 m. If s

_{1}slowly moved forward, the sound intensity decreases, then increases, reaching another maximum when s

_{1}is at x = 0.90 m.

a. What is wavelength

## Homework Equations

Δ∅=2π (Δx/λ) +Δ∅

_{0}=(m) 2π

## The Attempt at a Solution

**My Solution**[/B]

I used Δ∅=2π (Δx/λ) +Δ∅

_{0}=(m) 2π

I let m=1 when Δx=0.5m for equation 1 and m=0 when Δx=0.9m for equation 2. I manipulated they equations so each equaled Δ∅

_{0}and then set equations 1 and 2 equal to each other. Then I solved for λ=0.4m

**Person Online**

They just measured the two distances between maximum sound intensities in order to get wavelength. Now this makes sense to me (I think...) since it is essentially just measuring the distance between two crests. Is this reasoning wrong?

**More detailed version of my attempt**

1st situation, m=1, Δx

_{a}=0.5m

Δ∅=2π (Δx

_{a}/λ) +Δ∅

_{0}=2π (1)

I manipulated the equation so

Δ∅

_{0}=2π (1-(Δx

_{a}/λ)) Equation 1

2nd Situation, m=0, Δx

_{b}=0.9m

Δ∅=2π (Δx

_{b}/λ) +Δ∅

_{0}=2π (0)

Δ∅

_{0}= -2π (Δx

_{b}/λ) Equation 2

Then I set 1 and 2 equal to another and got wavelength