Two pencils of planes have a common plane

Click For Summary
SUMMARY

The discussion focuses on determining the parameter α for which the pencil of planes through the line AB, defined by points A(1, 2α, α) and B(3, 2, 1), shares a common plane with the pencil of planes through the line CD, defined by points C(−α, 0, α) and D(−1, 3, −3). The conditions for a common plane include parallelism of the two pencils or their intersection. The solution involves finding a plane that contains points A, B, and C, and ensuring point D also lies in that plane, thus fixing the value of α.

PREREQUISITES
  • Understanding of projective geometry concepts, specifically pencils of planes.
  • Familiarity with vector mathematics and line equations in three-dimensional space.
  • Knowledge of how to derive equations of planes from points in 3D.
  • Ability to solve systems of equations to find common solutions.
NEXT STEPS
  • Study the derivation of plane equations from three points in 3D space.
  • Learn about the conditions for parallelism and intersection of lines and planes.
  • Explore the concept of skew lines and their implications in three-dimensional geometry.
  • Investigate the use of determinants in solving systems of linear equations related to planes.
USEFUL FOR

Students and professionals in mathematics, particularly those studying geometry, linear algebra, or projective geometry, as well as anyone involved in solving geometric problems in three-dimensional space.

beglor
Messages
1
Reaction score
0

Homework Statement


Find the value of the parameter α for which the pencil of planes through the straight line AB has a common plane with the pencil of planes through the straight line CD, where A(1, 2α, α), B(3, 2, 1), C(−α, 0, α) and D(−1, 3, −3).

Homework Equations


Let Δ be a line given by two equations:
A1x+B1y+C1z+D1=0
A2x+B2y+C2z+D2=0
The collection of all planes containing a given straight line Δ is called the pencil of planes through Δ.
The plane π belongs to the pencil of planes through the line Δ if and only if there exists λ,μ∈ℝ such that the equation of the plane π is:
λ(A1x+B1y+C1z+D1)+μ(A2x+B2y+C2z+D2)=0

The Attempt at a Solution


I wrote the equations of the lines AB and CD. But I don't know the condition for a plane to be common to two pencil of planes in the same time.
 
Physics news on Phys.org
I took a course in projective geometry in 1959 taught by C. R. Wylie Jr. at the University of Utah. Never used it since and about the only thing I remember about it is the use of pencils of lines and pencils of planes. I always figured the terms came from projective geometry.
 
beglor said:

Homework Statement


Find the value of the parameter α for which the pencil of planes through the straight line AB has a common plane with the pencil of planes through the straight line CD, where A(1, 2α, α), B(3, 2, 1), C(−α, 0, α) and D(−1, 3, −3).

Homework Equations


Let Δ be a line given by two equations:
A1x+B1y+C1z+D1=0
A2x+B2y+C2z+D2=0
The collection of all planes containing a given straight line Δ is called the pencil of planes through Δ.
The plane π belongs to the pencil of planes through the line Δ if and only if there exists λ,μ∈ℝ such that the equation of the plane π is:
λ(A1x+B1y+C1z+D1)+μ(A2x+B2y+C2z+D2)=0

The Attempt at a Solution


I wrote the equations of the lines AB and CD. But I don't know the condition for a plane to be common to two pencil of planes in the same time.
There will be a common plane if either
  1. the pencil of planes through the line AB is parallel to the pencil of planes through CD, or
  2. the pencil of planes through the line AB intersects the pencil of planes through CD
In case 1, the vector ##\overrightarrow{AB}## will be a scalar multiple of the vector ##\overrightarrow{CD}##.
In case 2, the equations of the two lines have to have a common solution.

If the lines are skew, there can't be a common plane.

I think I've covered all the possibilities...
 
beglor said:

Homework Statement


Find the value of the parameter α for which the pencil of planes through the straight line AB has a common plane with the pencil of planes through the straight line CD, where A(1, 2α, α), B(3, 2, 1), C(−α, 0, α) and D(−1, 3, −3).

Homework Equations


Let Δ be a line given by two equations:
A1x+B1y+C1z+D1=0
A2x+B2y+C2z+D2=0
The collection of all planes containing a given straight line Δ is called the pencil of planes through Δ.
The plane π belongs to the pencil of planes through the line Δ if and only if there exists λ,μ∈ℝ such that the equation of the plane π is:
λ(A1x+B1y+C1z+D1)+μ(A2x+B2y+C2z+D2)=0

The Attempt at a Solution


I wrote the equations of the lines AB and CD. But I don't know the condition for a plane to be common to two pencil of planes in the same time.

You want to find a plane that contains both lines AB and CD, so contains the four points A, B, C and D. It is a standard exercise to find the plane containing the three points A, B and C; then you can fix ##\alpha## by requiring that the fourth point, D, must also lie in the same plane.
 

Similar threads

Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
14K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
10K
  • · Replies 4 ·
Replies
4
Views
54K
  • · Replies 10 ·
Replies
10
Views
5K