Two Physics problems related to gravitational energy

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chroncile
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Homework Statement


1.) How fast must a rocket leave the Earth’s surface to reach a maximum height of 895 km above the surface of the Earth (assume the rocket is simply going straight up)?

The answer is 3920 m/s

2.) How fast must a rocket leave the Earth’s surface to reach an orbit with an altitude of 895 km above the surface of the Earth?

The answer is 8380 m/s


Homework Equations


EG = -GMm / r


The Attempt at a Solution


For 1.)

Ek + EG = Ek' + EG'
0.5v2 = GM / r
V = square root ((2 * G * 5.97*x10^24)/895000+6370000)
V = 10,470 m/s

For 2.)

I have no idea
 
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What you did for `1,' was you found the energy the rocket needed to end up with, then you figured out what velocity that corresponds to. You can do the same thing for `2,' just think: what's different about the final energy of the rocket in '2' as apposed to '1.'
 
But I didn't even get the right answer in question 1.
 
chroncile said:
But I didn't even get the right answer in question 1.
Good point. What is the initial potential energy? Then what is the final?