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Two Power / Work / Energy Questions

  1. Apr 1, 2006 #1
    Hey there, this is my post so I hope it does not seem like I am just asking for help without me trying to do work too.

    Ok, the kinetic energy of a car is 8 x 10^6 J as it travels along a horizontal road. How much work is required to stop the car in 10s? That is the question and I am not sure about how I can solve it with Power and Work.

    I know that Work = ΔE so we would have using kinetic energy

    W = (1/2)mvf^2 - (1/2)mvo^2
    W = (1/2)m(0m/s)^2 - 8 x 10^6 J
    W = 0 - 8 x 10^6 J
    W = -8 x 10^6 J

    Is that just the answer? What is the 10s for? Is it just extraneous information?

    Can someone just make sure I am answering this question correct

    A 1,500 kg car travels at a constant speed of 22 m/s around a circular track that is 80m across. What is the kinetic energy of the car?

    KE = (1/2)(m)(v)^2
    KE = (1/2)(1500kg)(22m/s)^2
    KE = 3.6 x 10^5 J

    Thank you.
  2. jcsd
  3. Apr 1, 2006 #2


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    For the first question:

    [tex]Power = \frac{{Work}}{{Time}}[/tex]

    So you know the work, you can implement the time to determine the power.
  4. Apr 1, 2006 #3
    Yes I realise that, however, the question asks for the work required, not the power.
  5. Apr 1, 2006 #4


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    Gold Member

    Well then you have the answer... kinda odd to just basically give you the answer in the question though
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