Hey there, this is my post so I hope it does not seem like I am just asking for help without me trying to do work too. Ok, the kinetic energy of a car is 8 x 10^6 J as it travels along a horizontal road. How much work is required to stop the car in 10s? That is the question and I am not sure about how I can solve it with Power and Work. I know that Work = ΔE so we would have using kinetic energy W = (1/2)mvf^2 - (1/2)mvo^2 W = (1/2)m(0m/s)^2 - 8 x 10^6 J W = 0 - 8 x 10^6 J W = -8 x 10^6 J Is that just the answer? What is the 10s for? Is it just extraneous information? Can someone just make sure I am answering this question correct A 1,500 kg car travels at a constant speed of 22 m/s around a circular track that is 80m across. What is the kinetic energy of the car? KE = (1/2)(m)(v)^2 KE = (1/2)(1500kg)(22m/s)^2 KE = 3.6 x 10^5 J Thank you.