- #1

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- Homework Statement
- In the circuit of the figure knowing that ##V_0=10\, \textrm{V}## determine ##V_S## and the power generated by the source ##J##.

Sol: ##V_S=-4\, \textrm{V}##, ##P_J=60\, \textrm{W}##

- Relevant Equations
- Kirchoff law

Figure:

My attempt at a solution:

1st kirchoff law:

$$J=2I_0+I_0=6\, \textrm{A}$$

$$V_1+8=10\rightarrow \boxed{V_1=2}$$

$$V_1=6-V_S\rightarrow \boxed{V_S=-4\, \textrm{V}}$$

We are looking for ##P## generated in ##J##

$$V_J=V_1-2\cdot J=2-2\cdot 6=-10\, \textrm{V}$$

$$\boxed{P_{\textrm{gen}}=(V_J-0)J=-10\cdot 6=-60\, \textrm{W}}$$

Wouldn't this exercise do like this? I have tried it but the power is negative.

My attempt at a solution:

1st kirchoff law:

$$J=2I_0+I_0=6\, \textrm{A}$$

$$V_1+8=10\rightarrow \boxed{V_1=2}$$

$$V_1=6-V_S\rightarrow \boxed{V_S=-4\, \textrm{V}}$$

We are looking for ##P## generated in ##J##

$$V_J=V_1-2\cdot J=2-2\cdot 6=-10\, \textrm{V}$$

$$\boxed{P_{\textrm{gen}}=(V_J-0)J=-10\cdot 6=-60\, \textrm{W}}$$

Wouldn't this exercise do like this? I have tried it but the power is negative.