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Wara
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pulley
Two masses are attached together by means of light inextensible strings and light frictionless pulleys as shown in the diagram. The system is released and the upper block slides along the table. The coefficient of friction between this block and the table is 0.32. Calculate the magnitude of the tensions (T1 and T2) and accelerations while the blocks are acceleration.
http://content.screencast.com/users/Waraa/folders/Snagit/media/bc6a12fc-dd79-4db6-91a4-1057f75aca6e/03.10.2012-15.11.45.png
(1) m1a1 = T1 - μmg
(2) m2aa = m2g - T2
(3) 2T1 = T2
(4) 2a2 = a1
T1 = 113.7N
T2 = 196N
(1) + (2) + (3) + (4)
m1a1 + m2aa + 2T1 + 2a2 = T1 - μmg + m2g - T2 + T2 + a1
2a2 = T1 - μmg + m2g + a1
I'm stuck right there. Am I even doing it right?
Homework Statement
Two masses are attached together by means of light inextensible strings and light frictionless pulleys as shown in the diagram. The system is released and the upper block slides along the table. The coefficient of friction between this block and the table is 0.32. Calculate the magnitude of the tensions (T1 and T2) and accelerations while the blocks are acceleration.
http://content.screencast.com/users/Waraa/folders/Snagit/media/bc6a12fc-dd79-4db6-91a4-1057f75aca6e/03.10.2012-15.11.45.png
Homework Equations
(1) m1a1 = T1 - μmg
(2) m2aa = m2g - T2
(3) 2T1 = T2
(4) 2a2 = a1
The Attempt at a Solution
T1 = 113.7N
T2 = 196N
(1) + (2) + (3) + (4)
m1a1 + m2aa + 2T1 + 2a2 = T1 - μmg + m2g - T2 + T2 + a1
2a2 = T1 - μmg + m2g + a1
I'm stuck right there. Am I even doing it right?
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