- #1

Kennedy

- 70

- 2

## Homework Statement

Two blocks, m1 = 1.0 kg and m2 = 2.0 kg are connected by a light string as shown in the figure. If the radius of the pulley is 1.0 m and its moment of inertia is of the system is 5.0 kg*m^2, the acceleration of the system is (expressed as a fraction of gravitational acceleration g):

## Homework Equations

I believe that Newton's Second Law is the only relevant equation (F = ma).

## The Attempt at a Solution

I have the acceleration to be in the direction of m2, because that's the heavier block. So, the m2g - T1 = m2a. Solving for T1 that leads to m2g - m2a = T1. On the other side of the pulley we have T2 - m1g = m1a. Solving for T2, we get T2 = m1a + m1g. Now the pulley, T2(radius) - T1(radius) = τ. We know that τ = Iα, and α = a/r.

Now, (m1a +m1g)(r) - (m2g -m2a)(r) = 5(a/r)

How do I solve this in terms of g?