Find the acceleration of the hanging block

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Homework Help Overview

The discussion revolves around finding the acceleration of a hanging block in a two-block/two-pulley system, with specific conditions such as massless pulleys and no friction. Participants are analyzing the forces acting on the blocks and the pulley, using free body diagrams and equations of motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss drawing free body diagrams for the blocks and the pulley, and they explore the relationships between tensions and accelerations. Some question the assumptions about the equal acceleration of the blocks and the need for multiple body diagrams. Others suggest practical experiments to visualize the problem.

Discussion Status

The discussion is ongoing, with various participants offering insights and corrections. Some have provided alternative equations and clarified the roles of different tensions in the system. There is no explicit consensus yet, but several productive lines of inquiry are being explored.

Contextual Notes

Participants are working under the constraints of a homework assignment, which emphasizes understanding the dynamics of the system rather than simply arriving at a solution. There is also mention of a diagram that is difficult to interpret, which may affect the clarity of the discussion.

  • #61
Emily_20 said:
Thank you so much! you're my genius hero lol. Thank you everyone else who helped me too I appreciate it very much you saved me!

You are welcome.:D
 
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  • #62
Emily_20 said:
I understand everything so far but I am confused about this part:" If m2 is pulled by 'x' distance then m1 is pulled by '2x' distance.

So a1=2a2." how did you know that the distance is 2x?

This part is confusing too.
1418ljc (2).jpg


If m2 is lowered down by 'x' then string on the left side of the pulley is increased by 'x' and string on the right side of the pulley is also increased by 'x'.
Hence, m1 covers distance 2x if m2 is lowered down by distance 'x'.

There are two pulleys here I am talking about the movable pulley.
 
  • #63
Emily_20 said:
a2=m2g/(4m1+m2) is the final answer correct?

Yes, ##a_{2}=\frac{m_{2}g}{4m_{1}+m_{2}}##
 
  • #64
Thank you, your awesome!
 
  • #65
Emily_20 said:
Thank you, your awesome!

You are welcome.:)
 

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