Satvik Pandey
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Emily_20 said:Thank you so much! you're my genius hero lol. Thank you everyone else who helped me too I appreciate it very much you saved me!
You are welcome.:D
The discussion focuses on calculating the acceleration of a hanging block in a two-block, two-pulley system, considering massless pulleys and no friction. The key equations derived include T1 = m1a1 for the first block and T2 - m2g = -m2a2 for the second block, leading to the relationship 2T1 = T2 for the pulley. The final acceleration formula established is a2 = m2g / (4m1 + m2), confirming the relationship between the accelerations of the two masses.
PREREQUISITESStudents studying physics, particularly those focusing on mechanics, as well as educators and tutors looking for examples of pulley systems and acceleration calculations.
Emily_20 said:Thank you so much! you're my genius hero lol. Thank you everyone else who helped me too I appreciate it very much you saved me!
Emily_20 said:I understand everything so far but I am confused about this part:" If m2 is pulled by 'x' distance then m1 is pulled by '2x' distance.
So a1=2a2." how did you know that the distance is 2x?
Emily_20 said:a2=m2g/(4m1+m2) is the final answer correct?
Emily_20 said:Thank you, your awesome!