Two stacked objects sliding down inclined plane.

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michaelwiggin
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Homework Statement


"A 60kg boy rides down an icy hill of 19º slope while standing on a 2.6kg flat-bottomed bathroom scale. Assume there is no frictional force between the bottom of the scale and the hill. The static friction force the scale exerts on the boy is ____.


Homework Equations


... F = ma
Ff=[tex]\mu[/tex]Fn
Not sure what else... really its the theory of it that's getting me.


The Attempt at a Solution


Well, my understanding is that if there was no friction between the boy and the top of the scale, then while the scale was sliding down the hill, the boy would be sliding downward not only with respect to the hill (as a result of the acceleration of the scale) but also with respect to the scale. But because it asks for the static friction of the scale on the boy, this must mean he's not moving, and thus when determining the friction we can use the usual Ff=mgsin[tex]\theta[/tex] equation.


Thus 60kg(9.8m/s2)(sin19) = 191.4

Any mistakes that you all notice?

Thanks!
-Michael
 
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>>Well, my understanding is that if there was no friction between the boy and the top of the scale
no, there is no frictional force between the scale and the ice hill

>>this must mean he's not moving
yes, relative the the scale he is not moving
 
The scale is not an inertial frame of reference as it is accelerating with respect to the stationary ground. If you stick to the scale as frame of reference, there is a force of inertia -ma acting on each body of mass m where a is the acceleration of the scale along the slope. You have gravity, the force of inertia, normal force and static friction acting on the boy. The sum of these forces must give zero.

ehild
 
You're correct ehild, my initial thinking was completely foolish. Somehow I believed that if frictionless plates (any objects I suppose) were stacked atop each other upon an inclined plane, than *each* accelerated with respect to the surface that they were placed on. That's absurd, of course, because if 100 plates were stacked then the top one would be accelerating at a rate of 981 m/s^2.*facepalm*The force of static friction is 0. Thanks fellas.
-Michael