Two wires in parallel and capacitence

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SUMMARY

The capacitance per unit length for two identical wires of radius d, separated by a distance D, is given by the formula C/l = (π ε₀) / (ln[(D - d) / d]). The discussion highlights the approach to derive this formula by calculating the potential difference V between the wires using the equation φ = 2λ ln(r/d) in Gaussian units, where λ represents the charge per unit length. The final relationship C/l = λ/V is established, confirming the capacitance calculation for the specified configuration of wires.

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I have to show that the capacitance per unit length for two identical wires of radius d separated (at the center) a distance D as:

C/l = (pi epsilon0) / ( ln [( D - d ) / d]

And I'm clueless. How do I go about solving this?

I started by trying with C = q / V to C = lambda * l / V .. but I didn't get far as I didn't know what to do with lambda.

Edit: they are oppositely charged, and the charge is distributed evenly along the surface of each wire.
 
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Calculate the potential difference V between the two wires
using phi=2\lambda ln(r/d) (in Gaussian units) for each wire.
Then C/l=\lambda/V
 

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