Uncertainty in Measuring Radioactivity: Calculating and Interpreting Results

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SUMMARY

The physicist measures the activity of a potentially radioactive rock by counting 225 particles in 10 minutes and 90 particles in 6 minutes. After converting these counts to rates, she calculates the rock's activity to be 400 particles per hour. To determine the uncertainty, she must apply Poisson statistics, adding the counting errors from both measurements in quadrature. This method confirms whether there is significant evidence of radioactivity in the rock.

PREREQUISITES
  • Understanding of Poisson statistics and counting errors
  • Familiarity with particle detection methods
  • Basic knowledge of radioactive decay and measurement techniques
  • Ability to perform calculations involving rates and uncertainties
NEXT STEPS
  • Research "Poisson statistics counting errors" for detailed methodologies
  • Learn about "background radiation measurement techniques" to improve accuracy
  • Study "uncertainty propagation in measurements" for better error analysis
  • Explore "radioactive decay laws" to understand the implications of measured activity
USEFUL FOR

Physicists, students in nuclear science, and researchers involved in radioactivity measurements and analysis.

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Homework Statement


To measure the activity of a rock thought to be radioactive, a physicist puts the rock beside a detector and counts 225 particles in 10 minutes. To check for background, she removes the rock and then records 90 particles in 6 minutes. She converts both these answers into rates, in particles per hour, and takes their difference to give the activity of the rock alone. What is her final answer, in particles per hour, and what is its uncertainty? Does she have significant evidence that the rock is radioactive?

The Attempt at a Solution



With stone she measures 1350 particles and hour and without the stone 900, so the rock alone should be 400 particles an hour. How do you calculate the uncertainty in this case? It seems to me calculating the standard deviation wouldn't work, because they are two entirely different measurements (with rock and without rock).
 
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Does your class notes or textbook talk about the uncertainty in counting experiments?
 
Yes, counting errors will be poissonian, and you would add the errors from the background and total in quadrature. check your book or google something like "Poisson statistics counting errors"
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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