Understand a Conceptual question on Scattering

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SUMMARY

This discussion focuses on the conceptual understanding of repulsive scattering, specifically regarding alpha particles and their interaction with a nucleus. The key point is that at the closest approach, the kinetic energy of the alpha particle is zero, indicating a complete conversion of kinetic energy into potential energy. The discussion emphasizes the importance of elastic scattering assumptions, which imply no energy losses, in calculating the distance of closest approach. Participants are encouraged to derive an expression for the potential energy of the system and identify the charge of the alpha particle.

PREREQUISITES
  • Understanding of classical mechanics principles, particularly energy conservation.
  • Familiarity with the concept of elastic scattering in physics.
  • Knowledge of potential energy equations in electrostatics.
  • Basic understanding of nuclear physics and alpha particle properties.
NEXT STEPS
  • Derive the potential energy expression for a nucleus-alpha particle system.
  • Study the principles of elastic scattering and its implications in particle physics.
  • Explore the characteristics and charge of alpha particles in detail.
  • Investigate the mathematical modeling of scattering events in nuclear physics.
USEFUL FOR

This discussion is beneficial for physics students, educators, and researchers interested in nuclear interactions, scattering theory, and energy conservation principles in particle physics.

claymine
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Homework Statement
Hi I am totally lost here, my answer matches with one of the choice but i think my reasoning is total bs please help me
Relevant Equations
# 19
Homework Statement: Hi I am totally lost here, my answer matches with one of the choice but i think my reasoning is total bs please help me
Homework Equations: # 19

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For this particular repulsive scattering, at closest approach, the kinetic energy of the alpha particle is zero, and all of the kinetic energy has been converted to potential energy. The alpha particle then returns back from where it came=180 degree scattering. For practical purposes, you can assume elastic scattering=no energy losses in computing the distance of closest approach. ## \\ ## Can you write an expression for the potential energy of the system consisting of the nucleus and the alpha particle? What is the charge of the alpha particle?.
 
Last edited:
What was your reason behind your choice?
 

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