Understand a Conceptual question on Scattering

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The discussion revolves around a conceptual question regarding repulsive scattering involving an alpha particle and a nucleus. The participant expresses confusion about their reasoning despite matching an answer choice. Key points include the understanding that at the closest approach, the alpha particle's kinetic energy becomes zero, converting entirely to potential energy, leading to 180-degree scattering. The conversation emphasizes the need to write an expression for the potential energy of the system and clarify the charge of the alpha particle. Overall, the discussion seeks to clarify the principles of elastic scattering and energy conversion in this context.
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Homework Statement
Hi I am totally lost here, my answer matches with one of the choice but i think my reasoning is total bs please help me
Relevant Equations
# 19
Homework Statement: Hi I am totally lost here, my answer matches with one of the choice but i think my reasoning is total bs please help me
Homework Equations: # 19

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For this particular repulsive scattering, at closest approach, the kinetic energy of the alpha particle is zero, and all of the kinetic energy has been converted to potential energy. The alpha particle then returns back from where it came=180 degree scattering. For practical purposes, you can assume elastic scattering=no energy losses in computing the distance of closest approach. ## \\ ## Can you write an expression for the potential energy of the system consisting of the nucleus and the alpha particle? What is the charge of the alpha particle?.
 
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What was your reason behind your choice?
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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