Understand Laplace alot better now

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SUMMARY

The discussion centers on the application of the Laplace transform to functions involving step functions and other terms. Specifically, it clarifies that when transforming a function like g(t) = t^2 * sin(3t) * x(t), where x(t) has an existing Laplace transform, x(t) must be included in the transformation. The conversation also distinguishes between the treatment of unit step functions u(t) and shifted step functions u(t-a), emphasizing that u(t) can be treated as 1 during integration, while u(t-a) requires careful consideration. The importance of understanding convolution integrals in this context is also highlighted.

PREREQUISITES
  • Understanding of Laplace transforms and their properties
  • Familiarity with unit step functions and their role in Laplace transforms
  • Knowledge of convolution integrals and their applications
  • Basic calculus, particularly integration techniques
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  • Study the properties of the Laplace transform, focusing on the inclusion of functions like x(t)
  • Learn about the implications of using shifted unit step functions in Laplace transforms
  • Explore convolution integrals and their significance in signal processing
  • Review examples of Laplace transforms involving multiple terms and functions
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Students and professionals in engineering, mathematics, and physics who are working with Laplace transforms, particularly those dealing with complex functions and convolution integrals.

mathrocks
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Ok, I'm starting to understand Laplace a lot better now. But I have, hopefully, my last question. If you have a function like

g(t)=t^2 * sin(3t) * x(t) where x(t) has an already defined laplace transform.

do you actually include x(t) in your laplace transformation? Because when I see other problems that have u(t) at the end you don't really do anything with them, you only worry about the terms in front of it. Like f(t)=sin(3t)u(t), the answer is simply 3 / (s^2 + 9)...u(t) is not included in it.
 
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mathrocks said:
g(t)=t^2 * sin(3t) * x(t) where x(t) has an already defined laplace transform.

do you actually include x(t) in your laplace transformation?

Yes, you do.

Because when I see other problems that have u(t) at the end you don't really do anything with them, you only worry about the terms in front of it. Like f(t)=sin(3t)u(t), the answer is simply 3 / (s^2 + 9)...u(t) is not included in it.

That's because u(t)=1 over the entire range of integration in the transform. If you had instead u(t-a), a>0, then you could not just drop it.
 
Tom Mattson said:
That's because u(t)=1 over the entire range of integration in the transform. If you had instead u(t-a), a>0, then you could not just drop it.


So for the problem:
g(t)=t^2 * sin(3t) * x(t)

How would you go about transforming that? This is my first encounter of 3 terms...
 
yeah, you'll probably need to review the chapter the step functions/laplace.

By the way, ever heard of convolution integrals?
 

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