Understand Newton's law of universal gravitation

Click For Summary

Homework Help Overview

The discussion revolves around Newton's law of universal gravitation, specifically calculating the gravitational force acting on the Earth due to the sun. The problem involves the masses of the Earth and the sun, their separation distance, and the gravitational constant.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of gravitational force using the formula F = G(mE)(mS)/r^2. There are attempts to verify the calculations, with one participant suggesting a potential calculator error in the exponent. Another participant questions the interpretation of variables in a subsequent problem, particularly regarding the radius of the Earth and the forces acting on an object.

Discussion Status

Some participants have provided guidance on checking calculations and interpreting the problem's requirements. There is an ongoing exploration of the assumptions related to the radius of the Earth and the nature of the forces involved.

Contextual Notes

There is a request for clarification on the entire problem statement, indicating that some information may be missing or unclear. Participants are encouraged to provide the complete context for better assistance.

aligass2004
Messages
236
Reaction score
0

Homework Statement


http://i241.photobucket.com/albums/ff4/alg5045/1012540B.jpg

Consider the Earth following its nearly circular orbit (dashed curve) about the sun. The Earth has mass 5.98 *10^24 kg and the sun has mass 1.99 *10^30 kg. They are separated, center to center, by r=93 million miles=150 million km. What is the size of the gravitational force acting on the Earth due to the sun?

Homework Equations



F = G(mE)(mS)/r^2

The Attempt at a Solution



Pretty much I just plugged and chugged to try to get the answer, which of course of was incorrect.

F = (6.67*10^-11)(5.98*10^24)(1.99*10^30)/ (1.5*10^11)^2 = 3.53*10^66
 
Physics news on Phys.org
Hi aligass2004,

aligass2004 said:

Homework Statement


http://i241.photobucket.com/albums/ff4/alg5045/1012540B.jpg

Consider the Earth following its nearly circular orbit (dashed curve) about the sun. The Earth has mass 5.98 *10^24 kg and the sun has mass 1.99 *10^30 kg. They are separated, center to center, by r=93 million miles=150 million km. What is the size of the gravitational force acting on the Earth due to the sun?

Homework Equations



F = G(mE)(mS)/r^2

The Attempt at a Solution



Pretty much I just plugged and chugged to try to get the answer, which of course of was incorrect.

F = (6.67*10^-11)(5.98*10^24)(1.99*10^30)/ (1.5*10^11)^2 = 3.53*10^66

I think you have a calculator error here. If you multiply these numbers together, you don't get an exponent of 66.
 
aligass2004 said:
That was the problem. Thank you!

http://i241.photobucket.com/albums/ff4/alg5045/1012540D.jpg

Now it asks for the value of the composite constant (GmE/r^2), to be multiplied by the mass of the object mO in the following equation?

http://i241.photobucket.com/albums/ff4/alg5045/render.gif

What is the statement of the problem?

I'm assuming re is not the radius of the earth, or you could just calculate that quantity from what you already have. Are the forces cancelling on that object, or is something else happening?
 
Last edited:
r is the radius of the earth. I still just don't understand what it's asking for.
 
If you can, please post the entire problem (all parts, even those that you may not have gotten too yet) exactly as its written, and maybe I or someone else can help you interpret it.

If all you need is the gravitational constant G times the mass of the Earth divided by the radius of the Earth squared, you can find those quantitites easily (they are usually inside the covers of the first-year physics textbooks).
 
"Now it asks for the value of the composite constant (GmE/r^2), to be multiplied by the mass of the object mO in the following equation?"


The solution to the composite constant is simply 9.8 m/s^2.

Convert the radius of 6.38*10^3 km to meters... which is 6,380,000 m
(GmE/r^2)= (6.67*10^-11)(5.98*10^24)/(6,380,000)^2

Calculate this and you will get 9.81 m/s^2
 

Similar threads

Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 23 ·
Replies
23
Views
4K