If two protons collide at the LHC and a quark from each undergo a weak interaction together to form a W/Z boson, then what happens to the remnants of the protons? I think that if the weakly interacted quark was a sea quark, then the proton can continue being itself, but may lead to jets. If, however, the weakly interacted quark was a valence quark, then the remnant of the proton must lead to jets since a valence u or d is missing. Ultimately, the final state will still contain two protons to conserve baryon number. Is this correct? Also, are the two quarks that form the W/Z "ripped out" of the proton or rather one proton enters the other so that the interaction could occur? That is to say, a volume of space normally occupied by one proton is temporarily occupied by two protons and also the newly created W/Z boson?