Understanding an instantanious velocity lab

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The lab involved measuring the instantaneous velocity of a car on a track using photo gates, with data collected from multiple runs at decreasing distances. The participant is confused about how to report the instantaneous velocity, particularly in relation to their velocity-time graph. To find the instantaneous velocity, they are advised to read the y-coordinate at the desired time on the graph or calculate the slope of the tangent on the position-time graph. They noted that their results showed variability, likely due to human error, but expected the average velocity to approach 0.6 m/s as the distance decreased. Clarification on these methods is essential for accurate reporting in their lab report.
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Hey, I did a lab yesterday, and I am working on the report right now, my problem is my teacher confused the hell out of me with what it is I need to have in the report.

the experiment was this:
We took a car and placed it on a track with a photo strip at the top, and sent it through a photo gate, this gave us the instantaneous velocity. Then we had to set it up so that the car went through two photo gates from 180cm until 10 cm, reducing the distance by 10cm each time.

So basically I have a value for what the instantaneous velocity should be from part A of the lab. From part B, I have a chart of 18 different runs, which gives change in time, distance and all that good stuff, and a graph of Velocity/Time. I did this in excel. What I need to find is the instantaneous velocity of the graph i think? I think that means I need to find the limit as t goes to 0 of my data, anyone know how to do that, or can point me in the right direction?
 
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I think you already have the velocity-time graph, just read the y-co-ordinate of the point on that curve that corresponds to the time t for which you want the instantaneous velocity. If you don't have the velocity-time graph, find the slope of the tangent of the position time graph. Use the method of least squares to fit a second degree curve (I suppose the car is accelerating, else you wouldn't need instantaneous velocity) and use that curve to find derivatives.
 
well I figured it would be constant a, but its not. but I assume that's human error, and the point of taking so many calculations was to show that Vbar would get closer to the number we wanted which was .6m/s as we approached 0m. I did forget to mention that in part A, we just took the measurement from 90cm away, and then we got to 95cm-85cm from the car as our last measurement
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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