Understanding and Solving the Taylor Series for a Specific Point

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Homework Help Overview

The discussion revolves around understanding the Taylor series, particularly how to calculate it about a specific point for a given function. Participants explore the concept of centering the series at different points and the implications for the coefficients and the series representation.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster seeks clarification on what it means to calculate the Taylor series about a particular point and requests examples. Some participants explain the general form of the Taylor series and provide specific examples, such as the series for the function f(x) = e^x.

Discussion Status

Participants are actively discussing the definition and calculation of the Taylor series about specific points. Some have provided explanations and examples, while others are encouraged to explore further by trying expansions at different points.

Contextual Notes

There is an emphasis on understanding the role of the center point in the Taylor series and how it affects the coefficients. The discussion includes a suggestion to compare expansions at different points, indicating a potential exploration of the concept.

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What does it mean to calculate the Taylor series ABOUT a particular point?

I understand the formula for the Taylor series but how do you solve it about a particular point for a function? It's the about the particular point that confuses me.

Could someone please explain this and provide examples?

Thanks!
 
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A Taylor series of a function f, about the point x = 0 is a representation of f as a sum of polynomials centered at x = 0, namely x, x^2, x^3, x^4, \ldots

Thus it will have the form

f(x) = a_0 + a_1 x + a_2 x^2 + a_3 x^3 + a_4 x^4 + \ldots

More generally, we can express f as a sum of polynomials centered at some other point, say x = c. Then it will look like

f(x) = a_0 + a_1 (x - c) + a_2(x - c)^2 + a_3 (x - c)^3 + a_4 (x - c)^4 + \ldots

This is a more general form: if I set c = 0 then it reduces to the previous equation. Note that the values of the coefficients generally change if I change c. Here is the formula for the k'th coefficient:

a_k = \frac{f^{(k)}(c)}{k!}

where f^{(0)} is taken to mean f, and f^{(k)} means the k'th derivative of f. So to calculate a_k, you find the k'th derivative of f and evaluate it at x = c.
 
As a simple example, take f(x) = e^x. This is a nice example because all of the derivatives also equal e^x. Thus, if I center the Taylor series at c, the coefficients will be
a_k = \frac{f^{(k)}(c)}{k!} = \frac{e^c}{k!}
and the series will therefore be
e^x = \frac{e^c}{0!} + \frac{e^c}{1!}(x - c) + \frac{e^c}{2!}(x - c)^2 + \ldots
For the special case c = 0, we have e^c = e^0 = 1 so the coefficient simplifies to
a_k = \frac{1}{k!}
and the series will therefore be
e^x = \frac{1}{0!} + \frac{1}{1!}x + \frac{1}{2!}x^2 + \ldots
 
The Taylor series is only defined to be about a particular point. The Taylor series expansion of y(x) about point x=a would be: $$y(x)_a = \sum_{n=0}^\infty \frac{f^{(n)}}{n!}(x-a)^n$$ It will be exact at that point - see:

220px-Exp_series.gif


... this is the Taylor series expansion (red line), taken about x=0, for the exponential function. See how after each term is added in, the red line has the same value as the blue at x=0? As an exercise, try doing the expansion for ##y(x)=e^x## about ##x=2##, and compare.
 

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