Understanding Angular Size Calculation: Europa and Jupiter

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Homework Help Overview

The discussion revolves around calculating the angular size of Jupiter as viewed from Europa, in comparison to the angular size of the Moon as viewed from Earth. The problem involves understanding the relationships between distances and diameters of celestial bodies.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the geometric relationships involved, including the use of similar triangles. Some suggest drawing diagrams to visualize the problem. Others mention the approximation of angular size for small angles using the ratio of diameter to distance.

Discussion Status

There are various approaches being explored, including the use of trigonometric functions to relate the angular sizes of the Moon and Jupiter. Some participants have provided calculations and expressions for the angular sizes, but there is no explicit consensus on the final interpretation or solution.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the extent of assistance provided. The original poster expresses confusion about the problem setup and seeks clarification on the calculations involved.

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i have a list of problems dealing with angular size that i have to complete, but I am a little confused on how exactly to solve them. if anyone could help me with this first example, it would be greatly appreciated. thank you (:

europa is about 1.7 times more distant from Jupiter than the moon is from earth, and jupiters diameter is 41 times larger than that of the moon. how large would Jupiter appear to you as standing on europa compared to the way a full moon looks as viewed from earth? finally, express this angular size in degrees considering the moons angular size is 0.5^0
 
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The problem is more about similar triangles and geometry than angular-size in particular. Try drawing a picture of the relative situations.
 
for very small angles the angular size in radians is approximately
diameter/distance
 
assume that angular size of moon is "a" :
tan (a)=(R1/D1)
R1 : diameter of moon
D1 : distance of moon-earth
and for Jupiter that angular size is "b" :
tan (b)=(R2/D2)
R2 : diameter of jupiter----> R2=41R1
D2 : distance of jupiter-europa ----> D2=1.7D1
so we have:
tan (b)=(41/1.7)(R1/D1)------> tan(b)=(41/1.7)tan (a)
so -----> b=11.88 degrees
 

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