- #1

Xcellerator

- 8

- 0

r=n^2xa

_{0}

where a

_{0}=0.0529

and that the wavelength for an electron with l=0 (circular orbit), is

λ=2∏r

so for n=1, λ=6.28a

_{0}.

So, following the same maths, for n=2, I get λ=2x∏x2^2=8∏a

_{0}.

However, according to http://hyperphysics.phy-astr.gsu.edu/hbase/bohr.html#c5, The answer is 4∏a

_{0}, which means that n is not squared.

Can anyone please explain whether or not n is squared to work out the orbital radius?