Understanding Bulk Modulus: Explaining the Relationship with Pressure and Volume

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The discussion revolves around the derivation of the bulk modulus (K) from the change in volume (delta V) and pressure (delta p) using the equations provided in the textbook. The first equation relates delta V to delta p, Poisson's ratio (c), and Young's modulus (E), while the second equation defines bulk modulus as K = -V dp/dV. The confusion arises in understanding how K is obtained by taking the limit as delta p approaches zero. It is clarified that the second equation is independent of the first, and the derivation involves applying generalized Hooke's law for isotropic materials. Ultimately, the bulk modulus for isotropic materials can be expressed as K = E / 3(1 - 2c).
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Homework Statement



My textbook says, delta V = [-3V delta p (1 - 2c)] /E
where,
delta V = change in volume
delta p = change in pressure
c = poisson's ratio
E = young's modulus

Taking the limit as delta p tends to zero, we can write the bulk modulus K as,
K = -V dp/dV

but I'm not clear with how they got K by taking the limit as delta p goes to zero...could someone explain that please. Thanks!
 
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The second equation isn't meant to follow from the first. The second equation is the definition of the bulk modulus. The first equation comes from using the generalized Hooke's equation for an isotropic material (in your notation):

\epsilon=\frac{1}{E}\sigma_1-\frac{c}{E}\sigma_2-\frac{c}{E}\sigma_3

where we plug in the pressure p for all three stresses. Also, the change in volume

\Delta V=(1+\epsilon)^3-1\approx3\epsilon

for small strains. The bulk modulus for an isotropic material would therefore be

K=\frac{E}{3(1-2c)}
 

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