Understanding Circular Motion: Force and Velocity in Orbits Explained"

  • Thread starter Thread starter allok
  • Start date Start date
  • Tags Tags
    Confusing
Click For Summary
Circular motion involves forces that can change the direction of an object's velocity without altering its speed, particularly in circular orbits where gravitational force is perpendicular to velocity. However, in elliptical orbits, gravitational force is not consistently perpendicular, leading to variations in speed as described by Kepler's second law. The discussion highlights the misconception that gravitational force is always perpendicular to velocity, emphasizing that when analyzing components of velocity and force, gravity can have a parallel component affecting speed. Clarifying these concepts is essential for understanding orbital mechanics. The conversation underscores the complexity of circular and elliptical motion in physics.
allok
Messages
16
Reaction score
0
hiya

Circular motion is really confusing

Force perpendicular to velocity is said to change only velocity's direction but not its magnitude. But how about object orbiting the earth? If object orbits the Earth then force of gravity is perpendicular to it and thus is said it only changes its direction.

Ok, so perpendicular force only can change direction of velocity because it doesn't have any components parallel to velocity. But:

if you break velocity vector of an orbiting object in components ( at any point on its path ) and also break force of gravity into components, then it becomes obvious that force of gravity always has component parallel to some comonent of object's velocity vector and as such it never really is perpendicular to velocity.

I need a little help people

thank you
 
Physics news on Phys.org
allok said:
hiya

Circular motion is really confusing

Force perpendicular to velocity is said to change only velocity's direction but not its magnitude. But how about object orbiting the earth? If object orbits the Earth then force of gravity is perpendicular to it and thus is said it only changes its direction.

Ok, so perpendicular force only can change direction of velocity because it doesn't have any components parallel to velocity. But:

if you break velocity vector of an orbiting object in components ( at any point on its path ) and also break force of gravity into components, then it becomes obvious that force of gravity always has component parallel to some comonent of object's velocity vector and as such it never really is perpendicular to velocity.

I need a little help people

thank you

If the orbit is circular, the force of gravity will always be perpendicular to the velocity. Pick any point of the orbit. The velocity is tangent to the circle along which the object is moving, right? And the force of gravity is always toward the center of the Earth. You can convince yourself that the force will always be perpendicular to the velocity and therefore the speed (the magnitude of the velocity) does not change.

If the orbit is elliptical, then yes, there are some points where the force is not perpendicular to the velocity and in that case the speed is not constant (in agreement with Kepler's second law of planetary motion)
 
allok said:
hiya

Circular motion is really confusing

Force perpendicular to velocity is said to change only velocity's direction but not its magnitude. But how about object orbiting the earth? If object orbits the Earth then force of gravity is perpendicular to it and thus is said it only changes its direction.
ONLY if the orbit is a circle. Most orbits are somewhat elliptical. Force is perpendicular to velocity only at the ends - where the ellipse intersects the major axis.

In an elliptical orbit the central force DOES change the magnitude of velocity because it is not always perpendicular to the velocity.

AM
 
allok said:
hiya
But:

if you break velocity vector of an orbiting object in components ( at any point on its path ) and also break force of gravity into components, then it becomes obvious that force of gravity always has component parallel to some comonent of object's velocity vector and as such it never really is perpendicular to velocity.
Make the X-axis in the direction of the speed and the y-axis in the direction of the gravity. You will see that they don't cancel each other out. And even if you choose different coords, you'll get the same resault cause all the gravity components in the direction of the velocity will cancel out.
 
"If object orbits the Earth then force of gravity is perpendicular to it and thus is said it only changes its direction."

It is this sentence by you which is flawed; the rest is well thought out.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
1
Views
781
Replies
8
Views
2K
Replies
11
Views
1K
  • · Replies 31 ·
2
Replies
31
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 12 ·
Replies
12
Views
910
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K