Understanding Complex Logarithms and Justifying Formulas

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Discussion Overview

The discussion revolves around the complexities of complex logarithms, including their properties, derivations, and implications. Participants explore the validity of specific formulas and the nature of logarithmic functions in the complex plane, touching on theoretical and conceptual aspects.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant proposes the formula ln(-a) = ln(a) + πi, questioning its validity and seeking feedback on their reasoning.
  • Another participant agrees that the formula is valid for positive real values of a, but notes it may vary by multiples of 2πi.
  • A participant raises a concern about the consistency of results when manipulating the formula, particularly when substituting different values for a.
  • Discussion highlights that the complex logarithm is multivalued, illustrated by the example of ln(1) yielding both 0 and 2πi.
  • One participant explains the general formula for complex logarithms, emphasizing the role of the argument and the multivalued nature of the function.
  • Concerns are raised about the application of logarithmic properties in the context of complex numbers, suggesting caution when using these properties without justification.
  • Another participant provides a derivation of the complex logarithm formula, reinforcing the connection between polar forms and logarithmic expressions.
  • Questions arise regarding the distinction between natural logarithms and logarithms of other bases in the context of complex analysis.

Areas of Agreement / Disagreement

Participants express varying views on the validity and implications of the proposed formulas. While some agree on certain aspects, such as the multivalued nature of complex logarithms, no consensus is reached on the broader implications or the specific applications of the formulas discussed.

Contextual Notes

Participants note that the properties of logarithms may not hold in the same way for complex numbers as they do for real numbers, particularly regarding the principal branch of the logarithm. The discussion also reflects uncertainty about the implications of using logarithmic properties in the complex plane.

Who May Find This Useful

This discussion may be of interest to students and professionals in mathematics, physics, and engineering who are exploring complex analysis, particularly those grappling with the intricacies of complex logarithms and their applications.

Hertz
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I've read about complex logarithms and maybe it's just my reading skill, but it all seems to be way too complicated. Anyways, after doing some thinking of my own I've come up with a few formulas, one of which is ln(-a) = ln(a) + πi; however, my reasoning behind such formulas seems way too basic, so I'm doubting myself. Could someone please check my work and let me know if what I'm doing is ok?

Here's the derivation:
ln(-a) = ln(-a)
ln(-a) = ln(-1a)
ln(-a) = ln(-1) + ln(a) -- Properties of Logs
ln(-a) = πi + ln(a) -- Euler's Identity

Euler's identity states e^(iπ) = -1; therefore, ln(-1) = iπ.
 
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So long as you restrict a to being positive and real, that formula should be valid. Well, up to a multiple of 2πi anyway.
 
Char. Limit said:
So long as you restrict a to being positive and real, that formula should be valid. Well, up to a multiple of 2πi anyway.

Wait a minute, that's an excellent point.. Why does the output of the function change depending on how you organized the terms?

ln(-a) = πi + ln(a)
If we attempt to let a = -1
ln(1) = πi + ln(-1)
ln(1) = 2πi

However, if we write ln(-1) = πi + ln(a) as
ln(a) = ln(-a) - πi
Now if we let a = 1 to solve for ln(1)
ln(1) = ln(-1) - πi
ln(1) = πi - πi
ln(1) = 0

Is 2πi the same as zero? Looking at Euler's Identity I've never seen the π as evidence of a cycle, I've always just thought of it as a constant. Interesting... That's something to think about..

e-
The formula is intended to work for all a, a != 0. Why must a be limited to positive values?
 
The complex logarithm is a tricky animal. First of all, it is multivalued. This can easily be seen by

e^0=1=e^{2\pi i}

So the logarithm of 1 should be both 0 and 2\pi i (and other values).

A formula for the complex logarithms can be given by

Log(z)=log|z| + i arg(z) + 2\pi i k

for all k\in \mathbb{Z} (that is: each k gives a good value for the logarithm).

The arg(z) is the angle that z makes with the positive x-axis in radians.

For example, if z is a positive real, then it makes a 0 angle with the positive x axis, and thus

Log(z)=log(z)+2\pi i k

if k=0, then this corresponds with the ordinary logarithm.

If z is a negative real, then it makes a \pi (or -\pi, doesn't matter) angle with the positive x-axis. And thus

Log(z)=log(-z)+\pi i + 2\pi i k

If k=0, then we get the formula you discovered.

Mathematicians don't like multi-valued functions, that's why they restrict the logarithm to only take on one value. That is: we always take k=0 in the previous formula. This is called the principal branch of the logarithm. This is a very arbitrary choice and other choice can be made. But it has as benefit that the complex logarithm coincides with the real logarithm for positive real numbers.

Also, complex logarithms are dangerous because many familiar laws do not hold anymore. For example, Log(zw)=Log(z)+Log(w) is not valid anymore (certainly not for the principal branch logarithm).
 
micromass said:
The complex logarithm is a tricky animal. First of all, it is multivalued. This can easily be seen by

e^0=1=e^{2\pi i}

So the logarithm of 1 should be both 0 and 2\pi i (and other values).

A formula for the complex logarithms can be given by

Log(z)=log|z| + i arg(z) + 2\pi i k

for all k\in \mathbb{Z} (that is: each k gives a good value for the logarithm).

The arg(z) is the angle that z makes with the positive x-axis in radians.

For example, if z is a positive real, then it makes a 0 angle with the positive x axis, and thus

Log(z)=log(z)+2\pi i k

if k=0, then this corresponds with the ordinary logarithm.

If z is a negative real, then it makes a \pi (or -\pi, doesn't matter) angle with the positive x-axis. And thus

Log(z)=log(-z)+\pi i + 2\pi i k

If k=0, then we get the formula you discovered.

Mathematicians don't like multi-valued functions, that's why they restrict the logarithm to only take on one value. That is: we always take k=0 in the previous formula. This is called the principal branch of the logarithm. This is a very arbitrary choice and other choice can be made. But it has as benefit that the complex logarithm coincides with the real logarithm for positive real numbers.

Also, complex logarithms are dangerous because many familiar laws do not hold anymore. For example, Log(zw)=Log(z)+Log(w) is not valid anymore (certainly not for the principal branch logarithm).

Hmm, so I should be sure when using properties of logs that I don't perform operations on imaginary logs unless I can justify the formula in the imaginary plane first?

I've seen this formula before but it's one of those ones where I take a look at it and shy away, but really it's not all that difficult. This post will surely give me a lot to think about. Thank you

(I think what I'm going to do next is try to generalize the familiar log formulas.)

P.s. The log above is considered to be the natural log right? Or is that formula a generalization for all bases?

e-
Two questions:
Is this operation ok?
ln(a) = ln(-1) + ln(-a)?
This is a basic rule of logarithms, but does the ln(-1) make the use of the rule questionable?

Do you have a proof of that formula? I'd like to see how it was derived.
 
Last edited:
Hertz said:
Hmm, so I should be sure when using properties of logs that I don't perform operations on imaginary logs unless I can justify the formula in the imaginary plane first?

Yes. I think most properties will hold for the multivalued log, but not for the principal branch. But it needs to be proven first.

I've seen this formula before but it's one of those ones where I take a look at it and shy away, but really it's not all that difficult. This post will surely give me a lot to think about. Thank you

It's really not hard. Take a complex number w. Denote

Log(w)=z

this means by definition that

e^z=w

Write z=z_1+iz_2. We can write w in its polar form as |w|(\cos\theta +i\sin\theta) where \theta is the arg of w. Thus we have

e^{z_1+iz_2}=|w|(\cos\theta+i\sin\theta)

By Eulers formula, we have

e^{z_1+iz_2}=e^{z_1}e^{iz_2}=e^{z_1}(\cos z_2 + i\sin z_2)

So we got the equation

e^{z_1}(\cos z_2 + i\sin z_2)=|w|(\cos\theta +i\sin\theta)

We deduce from this that e^{z_1}=|w| and thus z_1=log|w|. Also, we have that

\cos z_2 = \cos\theta~\text{and}~\sin z_2=\sin\theta

This implies that z_2=\theta+k2\pi for a certain k. Thus

Log(w)=log|w|+i(\theta+k2\pi)

which is the formula we wanted.

P.s. The log above is considered to be the natural log right? Or is that formula a generalization for all bases?

That is a formula for the natural log. I'm sure there are generalizations for other bases. But for some reason, other bases don't really show up much in complex analysis.
 

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