Understanding Coupled Oscillators: Solving for Forces on Two Masses

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Homework Help Overview

The discussion revolves around understanding the forces acting on two coupled oscillators, specifically two masses attached to springs. The original poster presents their approach to formulating the equations of motion for the system.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to derive the equations for the forces acting on each mass, considering their displacements and the spring constants. Some participants question the need for unstretched lengths in the equations to avoid unrealistic scenarios.

Discussion Status

The conversation is ongoing, with participants exploring the implications of the initial conditions and the setup of the problem. There is some agreement on the original poster's approach, but further clarification on the unstretched lengths is suggested.

Contextual Notes

Participants discuss the initial positions of the masses and their displacements, indicating that the masses start at a defined position before being moved. The need for unstretched lengths in the equations is a point of consideration.

Tuneman
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Ok here's the problemo:

|
|ooooo[m1]00000[m2]
| I have two masses attached to two springs, the "ooo"s are the springs, and the "[m]"s are the masses, the spring constants are the same , and so are the masses. I know to do the problem, the only thing is I am having trouble figuring out the equations of the forces on the two masses.I thought [tex]F_1 = -kx_1 + k(x_2 - x_1) , F_2 = kx_1 - kx_2[/tex]

where [tex]x_1[/tex] is the displacement to the right from [tex]m_1[/tex] and [tex]x_2[/tex] is the displacement to the right from [tex]m_2[/tex]
 
Last edited:
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You probably need some unstretched lengths in there somewhere otherwise your masses are going to be beating against the wall and each other.
 
Well they are at position zero as they appear in the picture and then they are moved to the right
 
Ah, ok, that works too. Looks like you have it right then.
 

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