Understanding Dipole Behavior in a Dielectric Medium

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SUMMARY

The discussion focuses on the behavior of a dipole moment \( p \) located at the center of a spherical cavity within a dielectric medium characterized by relative permittivity \( \epsilon_r \). It establishes that the potential in the dielectric is equivalent to that produced by an effective dipole moment \( p' = p \frac{3\epsilon_r}{2\epsilon_r + 1} \). Additionally, the electric field strength inside the cavity is defined as \( E = \frac{2(\epsilon_r-1)}{2\epsilon_r + 1} \frac{p}{4\pi\epsilon_0 a^3} \), which combines the dipole's influence with a uniform field. The solution approach involves applying boundary conditions for electric field \( E \) and electric displacement \( D \) to derive the necessary equations.

PREREQUISITES
  • Understanding of dipole moments in electrostatics
  • Familiarity with dielectric materials and their properties
  • Knowledge of boundary conditions in electrostatics
  • Proficiency in spherical harmonics and potential theory
NEXT STEPS
  • Study the derivation of effective dipole moments in dielectric media
  • Learn about boundary conditions for electric fields and potentials
  • Explore the application of spherical harmonics in electrostatics
  • Investigate the implications of relative permittivity on electric fields
USEFUL FOR

This discussion is beneficial for physics students, electrical engineers, and researchers focusing on electrostatics, particularly those studying dipole interactions in dielectric materials.

XCBRA
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Homework Statement


A dipole p is situated at thecentre of a spherical cavity of radius a in an infiite medium of relative permitivity \epsilon_r. show that the potential in the dielectric medium is the same as would be produced by a dipole p' immersed in a continuous dielectric, where

p'=p\frac{3\epsilon_r}{2\epsilon_r +1}

and that the field strength inside the cavity is equal to that which the dipole would produce in the absence of the dielectric, plus a uniform field E

E=\frac{2(\epsilon_r-1)}{2\epsilon_r + 1}\frac{p}{4\pi\epsilon_0a^3}.


Homework Equations





The Attempt at a Solution


I am not sure at all how to approach this question. I would like to say that I would use spherical harmonics but i am not sure how to apply them in this case.

Would it be possible to say that at large distances

V_2= -\frac{p\cos\theta}{4\pi\epsilon_0\epsilon_r r^2}

then to add then assume that outside the sphere that

V_2= -\frac{p\cos\theta}{4\pi\epsilon_0\epsilon_r r^2} + \frac{A_2\cos\theta}{r^2}

and inisde the sphere that

V_1= B_1 r \cos\theta + \frac{B_2\cos\theta}{r^2}

and then solve the problem using the boundary conditions for tangential E and perpendicular D?

I am really unsure of how to solve this and any help will be greatly appreciated.
 
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XCBRA said:
Would it be possible to say that at large distances V_2= -\frac{p\cos\theta}{4\pi\epsilon_0\epsilon_r r^2}then to add then assume that outside the sphere thatV_2= -\frac{p\cos\theta}{4\pi\epsilon_0\epsilon_r r^2} + \frac{A_2\cos\theta}{r^2}
Kind of. Since A_2 is unknown, you might as well just try the potential: V_2 = - \frac{p^{\prime} \cos\theta}{4\pi \epsilon_0 \epsilon_r r^2}, where p^{\prime} is unknown and to be solved.

The whole point of the problem is that at large r, the field looks like something due to some effective dipole moment p^{\prime}, whose value you are to find.

and inisde the sphere thatV_1= B_1 r \cos\theta + \frac{B_2\cos\theta}{r^2}and then solve the problem using the boundary conditions for tangential E and perpendicular D?I am really unsure of how to solve this and any help will be greatly appreciated.

D is okay, but instead of using E, it is easier to use the condition that V is continuous.

So now you have two equations but three unknown: B_1, B_2, and p^{\prime}. But one of them can be found by consider the limit r\to 0.
 
Last edited:
Ahh ok that makes a lot more sense, thank you for the help.
 

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