Understanding Force and Mass in Kangaroo Jumps

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Homework Help Overview

The discussion revolves around a physics problem involving the forces acting on a kangaroo during its jump, specifically focusing on the relationship between force, mass, and height achieved. The original poster expresses difficulty in visualizing the problem through a free body diagram and seeks clarification on the underlying logic.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the forces acting on the kangaroo and the implications of constant force during the jump. There are attempts to apply kinematic equations to analyze the motion, with some questioning the approach taken and expressing confusion over the calculations.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the forces involved, but there is no explicit consensus on the correct approach or solution at this stage.

Contextual Notes

Participants are navigating the complexities of the problem without a complete understanding of the necessary physics concepts, particularly in relation to free body diagrams and kinematic equations. There is an indication of imposed homework constraints, as the original poster is not seeking a direct answer but rather a deeper understanding of the logic involved.

danield
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Hey.. i am having problems solving the following question...

2) A 40-kg kangaroo exerts a constant force on the ground in the firs 60 cm of her jump, and rises 2.0 m higher. When she carries a baby kangaroo in her pouch, she cna rise only 1.8 m higher, What is the mass of the baby kangaroo?

I am not interested in the answer so much.. but in the logic of the problems.. i just can't do a free body diagram for them..
please help
,dan
 
Last edited:
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Well, for (1), which forces are acting on the crate? Further on, what does the constant velocity tell you about the forces acting on the body?
 
ok 1.. i could solve.. i used the equation of force applied+weight=force of friction, and i found force applied and the direction.
But I am still having trouble wiht 2)
 
Well I've been trying to do something like 2y/g=t^2, then V=y/t and then A=v/t, but i guess that is not working, i think I've been seeing it from the wrong angle, but any way i try i can't get the answer :(
 

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