Understanding Freely Falling Bodies: The Relationship Between S and t^2

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
3 replies · 9K views
ritwik06
Messages
577
Reaction score
0
1.For a freely falling body under gravity:
1.Why does the slope of S vs. t^2 gives g/2? Why not g itself?
2.Does the graph exhibit linear relationship?

I have studied that the slope of a velocity time graphy gives the acceleration directly. Now when we make a graph for S vs. t^2 from a graph of velocity-time for a freely falling body. So why does the slope of the graph obtained gives g/2?
 
Physics news on Phys.org
Think of the equation relating position and acceleration (kinematic equation) for a particle with zero initial velocity
 
cristo said:
Think of the equation relating position and acceleration (kinematic equation) for a particle with zero initial velocity

s=0.5*gt^2

right??