Understanding Functions: Evaluating f(x,y) for Real Numbers | Explained

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SUMMARY

The discussion centers on evaluating whether specific mathematical relations define functions. The first relation, f defined as the set of ordered pairs (x,y) where y = x², is confirmed to be a function due to its unique y value for each x value. Conversely, the second relation, f defined as (x,y) where x = y², is not a function because it does not provide a unique y value for each x; for instance, x = 2 yields y values of -2 and 2. The vertical line test is cited as a definitive method for determining the function status of these relations.

PREREQUISITES
  • Understanding of real numbers (R)
  • Knowledge of function definitions in mathematics
  • Familiarity with the vertical line test for functions
  • Basic algebraic manipulation and graphing skills
NEXT STEPS
  • Study the vertical line test in depth to evaluate functions
  • Explore the implications of unique outputs in function definitions
  • Learn about inverse functions and their properties
  • Investigate other mathematical relations and their function status
USEFUL FOR

Students of mathematics, educators teaching algebra, and anyone interested in understanding the foundational concepts of functions and their graphical representations.

mathstudent88
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Let f be the set of all ordered pairs (x,y) such that x and y belong to R and y = x2. Is this a function?
The same question, for f be the set of all ordered pairs (x,y) such that x and y belong to R and x=y2. Is this a Function?



I think for the first one y=x2 it is a function because there is a unique y value for every x value that is given.

For the second one, I think that x=y2 is not a function because there is not a unique y value for every x. Because if x=2 then y can = -2 and 2.

Is this right?

Thanks for the help!
 
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You are correct.

Also, the graph of y = [tex]x^{2}[/tex] passes the vertical line test.

The 2nd function's graph doesn't.
 
thank you!
 

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