Understanding Ionic Charges for Na, Cl, and Other Particles

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Determining the ionic charge of particles like sodium (Na) and chlorine (Cl) involves understanding their positions in the periodic table. Non-metallic elements, particularly noble gases, have a charge of 0, while moving leftward decreases the charge. For example, fluorine has a charge of -1, and oxygen has -2. As one continues left, the charges transition from negative to positive, with lithium exhibiting a +1 charge. Metallic elements present more complexity, as their ionic charges often require memorization. For instance, cobalt (Co) can have multiple ionic states (+1, +2, +3) based on its electron distribution. Understanding electron shell distribution is crucial; atoms tend to lose electrons from the highest energy shells to achieve a stable state. Learning these principles simplifies the process of determining ionic charges across various elements.
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I'm having a terribly difficult time figuring this out and I'm (ashamedly) sure it is quiet simple. How do I know or figure out the ionic charge of a particle. Such as Na or Cl.

How do I know if they are a minus 1 or positve 2 or what they are?
 
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Ah, well, this isn't too difficult.

For non-metallic elements, it's very easy. Noble Gases (the ones farthest to the right), have a charge of 0. Now, as you go to the left, the charge goes down (-1) for every column. Flourine has a charge of -1, Oxygen -2, and so on. When you get to -4, then it's +4/-4. and it starts decreasing as you keep going left. Lithium has a charge of +1 then.

For metallic elements, it gets difficult. There's really only one way to do it, memorize 'em. ;)
 
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for metallic elements , you have to know how to distribute electrons on atom's shells.
for exmple Cobalt(27Co] is known as a Metal with two usual ions : +1 , +2 , +3
that's becuase It's electronic distribution gois like this :
27Co = 1s2 2s2 2p6 3s2 3p6 4s2 3d7
as you know , every etom always try to get to the low energy situation , so , it would lose the electrons in the shell with highest energy , which are from the 4th orbit , in 4s2 , and since 3d is almost equal to 4s , so the atom might lose some electrons from it.
Therefore , B family always make +2 ions , beside other ions depending on the atomic number of the element.

also , when you learn how to distribute electrons on atom's shells , this ion things will become very easy for you , so I suggest you learn them .
Excuse my bad enlgish :wink: , I tried my best
 
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I came.across a headline and read some of the article, so I was curious. Scientists discover that gold is a 'reactive metal' by accidentally creating a new material in the lab https://www.earth.com/news/discovery-that-gold-is-reactive-metal-by-creating-gold-hydride-in-lab-experiment/ From SLAC - A SLAC team unexpectedly formed gold hydride in an experiment that could pave the way for studying materials under extreme conditions like those found inside certain planets and stars undergoing...

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