Understanding Isospin in Neutron/Proton System: T & T3

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Discussion Overview

The discussion revolves around the concept of isospin in the neutron/proton system, particularly focusing on the total isospin (T) and its third component (T3). Participants explore the implications of isospin values in two-nucleon systems, including the configurations of protons and neutrons and the resulting T and T3 values.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant explains that the neutron and proton are treated as different states of a single particle, the nucleon, with assigned isospin values.
  • Another participant expresses confusion regarding the statement that for any value of T3, the total isospin T can take values at least as great as |T3|, questioning how a two-proton system can have T = 0 or 1.
  • A participant clarifies that the two-proton system has T3 = +1, thus T cannot equal zero, and similarly for the two-neutron system with T3 = -1.
  • Another participant introduces the combinations of proton and neutron states that yield T3 = 0, suggesting that T3 = 0 can arise from specific combinations of nucleons.
  • A later reply indicates that the initial confusion has been resolved, thanking another participant for their help.

Areas of Agreement / Disagreement

Participants express differing views on the possible values of total isospin T for specific configurations of nucleons. There is no consensus reached on the interpretation of T and T3 values in all cases.

Contextual Notes

Some assumptions regarding the definitions of isospin and the configurations of nucleons may be implicit in the discussion. The mathematical steps leading to the conclusions about T and T3 values are not fully resolved.

malawi_glenn
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This is from Krane, p 389:

The neutron and the proton are treated as two different states of a single particle, the nucleon. The nucleon is assigned with a fictious spin vector, called isospin.

Nucleon has isospin number t = ½, a proton has m_{t} = 1/2 and neutron has m_{t} = - 1/2.

The isospin obeys the same rules for angular momentum vecotrs.

The third component of a nucleus isospin is:
T_{3} = \frac{1}{2} (Z-N)

For any value on T_{3}, the total isospin T can take any value at least as great as |T_{3} | [/tex].<br /> <br /> We consider as an example the two-nucleon system, which can have T of 0 or 1. There are thus four possible 3-axis components: T_{3} = 1(two protons); T_{3} = - 1(two neutrons), and two combinations with T_{3} = 0(one neutron and one proton). The first two states must have T = 1, while the latter two can have T = 0 and T =1.<br /> <br /> - - - <br /> <br /> Now this is really confusing me. I am think that the according to the statement: <i>For any value on</i> &quot; T_{3}, <i>the total isospin</i> T <i>can take any value at least as great as </i>|T_{3} | [/tex].&amp;quot; The two proton system can therefore have T = 0 or 1. And the same thing regarding the 2N system.&lt;br /&gt; &lt;br /&gt; And also how can there be two combinations of P-N that gives T_{3} = 0? And why isn&amp;#039;t just T = 0 allowed?&lt;br /&gt; &lt;br /&gt; Should I try to think &amp;quot;backwards&amp;quot;: &lt;i&gt;Given a value on T, what values of T_{3} can I have, and what combinations of N and P do they represent?&lt;/i&gt;&lt;br /&gt; &lt;br /&gt; Cheers&lt;img src=&quot;https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f644.png&quot; class=&quot;smilie smilie--emoji&quot; loading=&quot;lazy&quot; width=&quot;64&quot; height=&quot;64&quot; alt=&quot;:rolleyes:&quot; title=&quot;Roll Eyes :rolleyes:&quot; data-smilie=&quot;11&quot;data-shortname=&quot;:rolleyes:&quot; /&gt;
 
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"The two proton system can therefore have T = 0 or 1. And the same thing regarding the 2N system."

The two p system has T_3=+1, so T cannot equal zero.
The two n system has T_3=-1, so T cannot equal zero.
 
Last edited:
T_3=0 can come from the two different combinations
(pn+np)/sqrt{2} for T=1, and
(pn-np)/sqrt{2} for T=0.
 
okay, I think I got it now. Thanx a lot dude! =)
 

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