Understanding Lyaponov Time & Units

  • Context: Graduate 
  • Thread starter Thread starter LagrangeEuler
  • Start date Start date
  • Tags Tags
    Time Units
Click For Summary
SUMMARY

Lyapunov time is defined as the inverse of the largest Lyapunov exponent, which is dimensionless. However, confusion arises regarding the units of Lyapunov time, as it is presented in time units in some literature. The relationship between the growth of nearby trajectories in chaotic systems, represented by the equation ##\exp (\lambda t)##, implies that the Lyapunov exponent ##\lambda## should have dimensions of reciprocal time to maintain dimensional consistency. Despite the theoretical framework, many papers report Lyapunov exponents as dimensionless.

PREREQUISITES
  • Understanding of Lyapunov exponents and their significance in chaos theory.
  • Familiarity with exponential functions and their dimensional analysis.
  • Basic knowledge of dynamical systems and chaos theory.
  • Experience with mathematical modeling and simulation of chaotic systems.
NEXT STEPS
  • Research the mathematical foundations of Lyapunov exponents in chaos theory.
  • Explore dimensional analysis in the context of exponential growth functions.
  • Study the implications of dimensionless parameters in dynamical systems simulations.
  • Investigate the practical applications of Lyapunov time in real-world chaotic systems.
USEFUL FOR

Researchers, mathematicians, and physicists interested in chaos theory, as well as computer scientists working on simulations of dynamical systems.

LagrangeEuler
Messages
711
Reaction score
22
In wikipedia text Lyaponov time is defined as inverse of the largest Lyapunov exponent. I have some difficulties with the units. Lyaponov exponents are dimensionless? So Lyaponov time is also then dimensionless? Right? How then in wikipedia article we get Lyaponov time in time units? Could you get me some reasonable explanation?
 

Attachments

  • Lyaponov time.png
    Lyaponov time.png
    18.9 KB · Views: 357
Physics news on Phys.org
If the distance between nearby trajectories of a chaotic system grows like ##\exp (\lambda t)##, with ##\lambda## the Lyapunov exponent, then ##\lambda## should have dimensions of reciprocal time, shouldn't it? The argument of an exponential function has to be dimensionless, otherwise the terms of the expansion

##\exp (x) = 1 + x + \frac{1}{2}x^2 + \frac{1}{6}x^3 + \dots##

would have different dimensions.
 
Thanks. But always in papers, I saw just dimensionless Lyapunov exponents.
 
If you're simulating some theoretical dynamical system with a computer program, it doesn't really matter if you set the position coordinates, time and masses to be dimensionless.
 

Similar threads

Replies
8
Views
3K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 6 ·
Replies
6
Views
11K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 10 ·
Replies
10
Views
3K