Understanding Measure Theory with Rudin's Principles of Mathematical Analysis

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Elementary subsets in measure theory, as discussed in Rudin's "Principles of Mathematical Analysis," are likely finite unions of rectangles, forming a ring due to their closure under finite unions and relative complements. However, they do not qualify as a $\sigma$-ring because they are not closed under countable unions and intersections. For example, while the entire plane can be represented as a countable union of finite rectangles, it has infinite area, illustrating the failure of closure under countable unions. Additionally, the set of rational numbers within a segment or circle can be constructed using countable unions and intersections of rectangles. Understanding these distinctions is crucial for grasping the foundational concepts of measure theory.
OhMyMarkov
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Hello everyone, I needed to know more about measure theory so I'm reading in Rudin's Principle's of Mathematical Analysis, somewhere in the chapter, he says:

We let E denote the family of all elementary subsets of $R^p$... E is a ring, but not a $\sigma$-ring.

According to my understanding of what a $\sigma$-ring is, it is the union of infinitely many sets $A_i$, each belongs to this ring. In "slang" mathematical terms, given any subset in $R^p$, we can describe it as the union of infinitely many subsets in $R^p$.

Any help is appreciated!
 
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How are elementary subsets defined?
 
OhMyMarkov said:
According to my understanding of what a $\sigma$-ring is, it is the union of infinitely many sets $A_i$, each belongs to this ring.
First, you probably mean the family of such unions. Each union is a subset of the universal set, while a $\sigma$-ring is a family of subsets of the universal set. Second, you are describing a $\sigma$-ring generated by a ring. The standard definition just says that $\sigma$-ring is closed under countable unions.

OhMyMarkov said:
In "slang" mathematical terms, given any subset in $R^p$, we can describe it as the union of infinitely many subsets in $R^p$.
This is too "slang" and does not give much information. You need to specify which subsets are representable as countable unions and which subsets participate in the union. Of course, any subset is the union of infinitely many copies of itself, or the union of singletons of all its elements.

Finally, what is your question?
 
girdav said:
How are elementary subsets defined?
I don't know to be honest, it's the first time I come across this term. I tried searching for them too.My question is, why is it a ring, but not a $\sigma$-ring?
 
OhMyMarkov said:
I don't know to be honest, it's the first time I come across this term. I tried searching for them too.

My question is, why is it a ring, but not a $\sigma$-ring?
So, you are trying to prove something about a concept whose definition you don't know? Not a good idea...

My guess is that elementary sets are finite unions of rectangles. They form a ring because the family of elementary sets are closed under finite union and relative complements. However, they are not closed under countable unions and intersections. For one, the whole plane is a countable union of finite rectangles, but it has infinite area. For another, the set of rational number inside a segment and a circle can be formed from rectangles using countable unions and intersections.
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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