Understanding Ohm's Law and the Relationship between Resistance and Current

[runicle]

I need to prove how 1 ohm is equal to
1 J/C*A
-
J being Joules
C being coulombs
A being Amperes
-
So far I got this, tell me if I'm going in the right track.
-
1 J/C*A -- 1 kg*m/s^2 over C and A
-
Now how can I do the rest knowing that you can find an ohm by the equation R = p*L/A? I know that a coulomb is the inverse of 6.24*10^18 and its 1 A*s.

 

[dicerandom]

You're very close as it is, it might help to know what an Ohm is in terms of the base SI units: http://en.wikipedia.org/wiki/Ohms

 

[runicle]

Okay so i know 1 Ω = 1 V/A = 1 m2·kg·s–3·A–2
so...
1 kg*m/s^2 over CA

C = A*S

But why is 1 Ω = 1 V/A = 1 m2·kg·s–3·A–2 has "...s–3·A–2?" That's what I'm confused about. Can someone break it down for me?

 

[TZW85]

1 V = 1 J/C = 1 kg.m2.s-2.C-1

Since 1 A = 1 C/s,

1 V = 1 kg.m2.s-3.A-1

 

[runicle]

Oh! Now i see the picture! Thank you