Understanding Op-Amp Integrator: Why the Ramping Effect?

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SUMMARY

The discussion centers on the operational amplifier (op-amp) integrator circuit and its ramping effect, specifically in relation to the integration of input voltage over time. The output voltage corresponds to the voltage across the capacitor, which accumulates charge based on the input voltage and the time constant defined by the resistor-capacitor (RC) network. The ramping effect occurs due to the continuous integration of the input signal, leading to a linear increase or decrease in output voltage over time, contingent on the input voltage and the RC time constant.

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  • Understanding of op-amp circuit configurations
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ZeroScope
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I'm having trouble understanding how this actually works. I understand that it integrates the input voltage and that the output voltage is the same as the voltage passing over the capacitor in the circuit. What i don't understand is why this causes the ramping effect?
I'm thinking it may have to do with one voltage being integrated by the integrator with relation to the capacitor and the resistor which creates a different value for the voltage which then gets integrated...etc. which then causes different values which plotted on a graph would give the ramp effect.
Is this how it works? thanks for the help.
 
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I just realized i neglected the time that this takes to happen. As its due to a certain time interval I am not sure whether what i originally assumed is correct. Now I am confused as to where time fits in with all this.
 
Sorry i realized i didnt take the fact that it is time dependent into my assumption. In this case I am even more confused heh.
 
Does this help? Or do you still have specific questions about the simple inverting integrator:

http://courses.ece.uiuc.edu/ece486/labs/lab1/386_op_amp.pdf
 

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