Understanding Order of Operations in Algebra

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Homework Help Overview

The discussion revolves around understanding the order of operations in algebra, particularly in the context of evaluating a quadratic function with a negative coefficient. The original poster expresses uncertainty about how to handle the negative sign when substituting values into the function f(x) = -x^2.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to clarify whether to apply the exponent before or after applying the negative sign when evaluating the function for specific values. They also explore the implications of treating the negative sign as a multiplication by -1.

Discussion Status

Participants have provided guidance on the order of operations, confirming that the exponent should be applied first, followed by multiplication by -1. There is a shared understanding of rewriting the function as f(x) = -1*(x^2), and some participants express confidence in this interpretation.

Contextual Notes

The original poster mentions a lack of answers in the textbook they are using, which may contribute to their uncertainty. They also reference the acronym PEMDAS, indicating their familiarity with the basic order of operations.

Philoctetes
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Homework Statement



This is just a question about order of operations. I recently started working through Morris Kline's "Calculus: An Intuitive and Physical Approach", but unfortunately my algebra's a bit rusty and the book doesn't list answers. I searched around via Google but I couldn't find any answers to this particular question.

Homework Equations



f(x) = -x^2

The Attempt at a Solution



I'm not sure how to deal with the negative sign here or in similar equations. If I'm solving for x = some number, let's say 2 [i.e. f(2)], do I apply the exponent and then apply the negative sign (so the answer would be -4)? I remember something from school about how you can treat the minus sign as a -1 multiplied by whichever relevant quantities in some situations. In this case, I might rewrite the equation as f(2) = -1(2^2). Or, should I just treat the base as negative in this sort of situation, so the answer would be 4 (-2*-2)?

In the same way, if I'm entering f(-2), would it be -4 [-1(-2*-2)], or would it be 4 (negatives cancel each other out)?

Thanks, sorry if this question seems a bit trivial.
 
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f(x)= -1*(x^2)

do what is in the brackets first, in this case for x=2, get 22 then multiply by -1.
 
rock.freak667 said:
f(x)= -1*(x^2)

do what is in the brackets first, in this case for x=2, get 22 then multiply by -1.

I wasn't sure about this one (whether a unary prefix operator is lower in precedence than multiplication), but you appear to be correct. At least wikipedia.org says so too:

http://en.wikipedia.org/wiki/Order_of_operations

.
 
So you are you saying that is is correct to rewrite f(x) = -x^2 as f(x) = -1*(x^2)? I just want to make sure you didn't misunderstand my post. I remember the basic order of operations, at least as far as the acronym goes - PEMDAS. I know how to solve f(x) = -1*(x^2).
 
yes, -x^2 = -1*(x^2)
 
Okay, thanks all.
 

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