Understanding Phasor Analysis in RC Circuits

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In an RC circuit with a resistor and capacitor in series, the voltage phasor across the resistor is in phase with the current, while the voltage phasor across the capacitor lags the current phasor by 90 degrees. The total voltage across the circuit is the vector sum of the voltages across the resistor and capacitor, which complicates the analysis. The current flowing through both components is the same, allowing for the calculation of individual voltages using Vr = i * R and Vc = i * Xc. The complex impedance of the series circuit is represented as (R + jXc), enabling the determination of current using the applied voltage Eo. Understanding these relationships is crucial for accurate phasor analysis in RC circuits.
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I understand that the voltage phasor for a resistor is in phase with the current phasor in a simple ac circuit consisting of only an AC voltage source and the resistor.

I understand that the voltage phasor for a capacitor is pi/2 radians behind the current phasor for an AC circuit consisting of only an AC voltage source and a capacitor.

When an RC circuit consisting of a resistor and capacitor in series is analyzed, I don't understand how the above still holds. Both proofs were based on the fact that the voltage across each circuit element varies by E = E0*cos(wt), but now the sum of the voltages across each element vary by this NOT each individual voltage.

I feel like this is a pure assumption. Here are the links to the book proof. I have a problem with the second picture of the phasor diagrams.
http://imgur.com/wmjzJ6C
http://imgur.com/aeh1ESb
 
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We know that the same current, i, flows in series through the resistor and capacitor. We know the voltage across the resistor will be Vr = i * R. We know the voltage across the capacitor will be Vc = i * Xc, with phase lagging Vr by 90°. At this point we do not know the value of i.
When we realize the vector sum of Vr and Vc is the applied voltage, Eo = Vr + Vc, we can solve for i, which identifies the scale of the diagram.

If we know the value of R and Xc, then we know the complex impedance of the series combination is (R + jXc ).
The applied voltage is Eo, so i = Eo / (R + jX ).
 
Further to Baluncore's explanation, if you are analysing a series combination of impedances then assume a fixed current (maybe 1 amp) through both, and if analysing a parallel combination assume a fixed voltage (maybe 1 volt) across both.
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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