Understanding Plank's Constant and Its Application in Energy Calculations

  • Thread starter Thread starter HoboRobo
  • Start date Start date
  • Tags Tags
    Explain
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 2K views
HoboRobo
Messages
2
Reaction score
0
What am I doing wrong in this problem? Please explain to me what I am doing wrong. Thanks
h-bar is plank's constant.

E = (l(l+1)(h-bar^2))/2I (l = 1)

I = Mh*R^2 Mh = 1.67x10^(-24)g R = 161x10^(-10) cm

For I i got 4.33x10^-40

So when i plugged in I for the top equation, i got E = (1(1+1)(1.11x10^(-68)))/8.66x10^-40
which equaled to : 2.56351... x 10^-29
But I found out from a friend that E actually equals to -2.18x10^(-18) Joules

What am I doing wrong?
 
Physics news on Phys.org
It would help if you told us what the actual problem is. All I see is you plugging random numbers into random equations.

Edit: Okay, it makes more sense with a bit of formatting.
HoboRobo said:
h-bar is plank's constant.

E = (l(l+1)(h-bar^2))/2I (l = 1)

I = Mh*R^2
Mh = 1.67x10^(-24)g
R = 161x10^(-10) cm

For I i got 4.33x10^-40

So when i plugged in I for the top equation, i got E = (1(1+1)(1.11x10^(-68)))/8.66x10^-40
which equaled to : 2.56351... x 10^-29
But I found out from a friend that E actually equals to -2.18x10^(-18) Joules

What am I doing wrong?
You need to keep track of your units. You're not using SI units everywhere, so your answer isn't going to come out in Joules.