Understanding Plank's Constant and Its Application in Energy Calculations

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SUMMARY

This discussion focuses on the application of Planck's constant (h-bar) in energy calculations, specifically using the formula E = (l(l+1)(h-bar^2))/2I. The user calculated the moment of inertia (I) using Mh = 1.67x10^(-24)g and R = 161x10^(-10) cm, resulting in an incorrect energy value of 2.56351... x 10^-29. The correct energy value is -2.18x10^(-18) Joules, highlighting the importance of using consistent SI units throughout calculations to achieve accurate results.

PREREQUISITES
  • Understanding of quantum mechanics concepts, particularly Planck's constant.
  • Familiarity with the formula for energy in quantum systems: E = (l(l+1)(h-bar^2))/2I.
  • Knowledge of moment of inertia calculations, specifically I = Mh*R^2.
  • Proficiency in unit conversion and the significance of SI units in physics.
NEXT STEPS
  • Study the implications of Planck's constant in quantum mechanics.
  • Learn about the significance of SI units in scientific calculations.
  • Explore the derivation and applications of the energy formula E = (l(l+1)(h-bar^2))/2I.
  • Investigate common errors in unit conversions and their impact on physics problems.
USEFUL FOR

Students and professionals in physics, particularly those studying quantum mechanics, as well as educators looking to clarify energy calculations involving Planck's constant.

HoboRobo
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What am I doing wrong in this problem? Please explain to me what I am doing wrong. Thanks
h-bar is plank's constant.

E = (l(l+1)(h-bar^2))/2I (l = 1)

I = Mh*R^2 Mh = 1.67x10^(-24)g R = 161x10^(-10) cm

For I i got 4.33x10^-40

So when i plugged in I for the top equation, i got E = (1(1+1)(1.11x10^(-68)))/8.66x10^-40
which equaled to : 2.56351... x 10^-29
But I found out from a friend that E actually equals to -2.18x10^(-18) Joules

What am I doing wrong?
 
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It would help if you told us what the actual problem is. All I see is you plugging random numbers into random equations.

Edit: Okay, it makes more sense with a bit of formatting.
HoboRobo said:
h-bar is plank's constant.

E = (l(l+1)(h-bar^2))/2I (l = 1)

I = Mh*R^2
Mh = 1.67x10^(-24)g
R = 161x10^(-10) cm

For I i got 4.33x10^-40

So when i plugged in I for the top equation, i got E = (1(1+1)(1.11x10^(-68)))/8.66x10^-40
which equaled to : 2.56351... x 10^-29
But I found out from a friend that E actually equals to -2.18x10^(-18) Joules

What am I doing wrong?
You need to keep track of your units. You're not using SI units everywhere, so your answer isn't going to come out in Joules.
 

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