Understanding Pressure: Forces F1, F2, F3 and Their Effects on Surfaces

  • Context: Undergrad 
  • Thread starter Thread starter atavistic
  • Start date Start date
  • Tags Tags
    Forces
Click For Summary
SUMMARY

This discussion clarifies the concept of pressure as the magnitude of the vector sum of forces (F1, F2, F3) divided by area, particularly as the area approaches zero. It emphasizes that pressure acts perpendicular to a surface and is derived from the normal component of the vector sum of forces. The conversation also highlights the complexity of pressure calculations on curved surfaces, necessitating integration of normal forces to determine the net force. Additionally, it notes that in most fluids, pressure remains uniform in all directions.

PREREQUISITES
  • Understanding of vector summation in physics
  • Knowledge of pressure concepts in fluid mechanics
  • Familiarity with normal forces and their applications
  • Basic calculus for integration of forces on curved surfaces
NEXT STEPS
  • Study the principles of fluid statics and pressure distribution
  • Learn about vector calculus and its application in physics
  • Explore the concept of normal forces and their significance in pressure calculations
  • Investigate integration techniques for calculating forces on curved surfaces
USEFUL FOR

Students and professionals in physics, engineering, and fluid mechanics who seek to deepen their understanding of pressure dynamics and force interactions on surfaces.

atavistic
Messages
105
Reaction score
0
Suppose we have lots of forces F1,F2,F3 etc acting at a point. Then pressure would be the magnitude of vector sum divided by area , limit of area tending to zero or just sum of magnitude of individual forces divided by area, limit of area tending to zero.

Also if we are given a surface and pressure on it is P, then we say force on the surface is FA (but keep in mind my above doubt), what is the direction of this force?

Please tell me all the subtle points like these about pressure.
 
Physics news on Phys.org


The first part doesn't make a lot of sense - you can't really have more than one force at a point and a point has no area. It is also not usual to add three forces, assign an area to them, and call it "pressure", though it could make sense in some cases, such as where you have a distributed load on one side of an object and point loads on the other (such as a fish tank on a four-point stand).

For the second question - I don't see where you display a "doubt" in the first, so I'm not sure what you are asking. But pressure at a point in space goes in all directions. On a surface, it is measured/acts perpendicular.
 
Hi atavistic! :smile:
atavistic said:
Then pressure would be the magnitude of vector sum divided by area , limit of area tending to zero or just sum of magnitude of individual forces divided by area, limit of area tending to zero.

Not quite …

pressure is the magnitude of the component of the vector sum in the normal direction, divided by area …
Also if we are given a surface and pressure on it is P, then we say force on the surface is FA (but keep in mind my above doubt), what is the direction of this force?

(you mean PA, i assume? :wink:)

The normal direction :smile:

though obviously, if the surface is curved, you'll have to do an integration of these normal forces to get a net force on the surface. :wink:

(but in most fluids, the pressure is the same in every direction :wink:)
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K