Understanding Probability Density Equation & Example

Click For Summary
SUMMARY

The discussion centers on the probability density equation, specifically the expression for the probability current density, given by \(\vec j = \frac{\hbar}{2mi}\left(\Psi^* \vec \nabla \Psi - \Psi \vec \nabla \Psi^*\right)\). Participants clarify that \(\Psi\) represents a position-space wavefunction, not a ket, and provide an example using the 1D infinite square well, where \(\psi_n(x)=\sqrt{2/L}~\sin(n \pi x/L)\). The gradient operator applied to a scalar field results in a vector field, confirming the vector nature of the output.

PREREQUISITES
  • Understanding of quantum mechanics terminology, specifically wavefunctions.
  • Familiarity with the concept of probability density in quantum mechanics.
  • Knowledge of vector calculus, particularly the gradient operator.
  • Basic principles of the 1D infinite square well model in quantum physics.
NEXT STEPS
  • Study the derivation of the probability density equation in quantum mechanics.
  • Learn about the implications of the gradient operator in quantum wavefunctions.
  • Explore the properties of the 1D infinite square well and its wavefunctions.
  • Investigate the relationship between wavefunctions and probability currents in quantum systems.
USEFUL FOR

Students and professionals in quantum mechanics, physicists analyzing wavefunctions, and anyone interested in the mathematical foundations of probability density in quantum systems.

ehrenfest
Messages
2,001
Reaction score
1
I am confused about the the probability density equation:

\vec j = \frac{\hbar}{2mi}\left(\Psi^* \vec \nabla \Psi - \Psi \vec \nabla \Psi^*\right)

Psi is not a ket on the right side, correct?
If not how can perform a del on it and get a vector on the right side?

Can someone give me a concret example of what you would plug into this expression:
\Psi^* \vec \nabla \Psi
 
Physics news on Phys.org
Psi is not a ket, it is a position-space wavefunction, given by the inner product: \psi _n(x) = \langle x|n \rangle

E.g., in the 1D infinite square well of width L, \psi_n(x)=\sqrt{2/L}~sin(n \pi x/L)

The gradient of a scalar field is a vector field.
 

Similar threads

Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
Replies
16
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
95
Views
8K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
7
Views
3K
  • · Replies 39 ·
2
Replies
39
Views
9K