Understanding Projectile Motion: Calculating Time and Velocity

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SUMMARY

The discussion focuses on calculating time and velocity in projectile motion, specifically addressing the horizontal velocity of 33.97 m/s as the constant value used for time calculations. Participants clarify that while the initial velocity is 42 m/s, it varies throughout the projectile's flight due to the influence of vertical acceleration. The correct calculation for the time taken to travel a horizontal distance of 170 meters is confirmed as 5 seconds, using the formula time = distance/velocity.

PREREQUISITES
  • Understanding of basic physics concepts, particularly projectile motion.
  • Familiarity with velocity and acceleration calculations.
  • Knowledge of horizontal and vertical components of motion.
  • Ability to perform basic algebraic calculations.
NEXT STEPS
  • Study the principles of projectile motion in detail.
  • Learn how to resolve vectors into horizontal and vertical components.
  • Explore the effects of gravity on vertical motion in projectiles.
  • Practice solving problems involving time, distance, and velocity in projectile scenarios.
USEFUL FOR

Students studying physics, educators teaching projectile motion, and anyone interested in understanding the dynamics of objects in motion.

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http://s359.photobucket.com/albums/oo40/jsmith613/?action=view&current=PhysQuestion.jpg

it should say "show that the" NOT "sow that the"

The horizontal velocity is 33.97 m/s. (34 m/s)
Why do I use this value to calculate time to travel from C to G and not the initial 42 m/s.
Is it because the 33.97 m/s value is constant throughout the entire journey of the ball, BUT the 42 m/s value is only true for my initial and final velocity. In between, however, the value 42 m/s is different. This is true because the combined horizontal velocity and vertical velocity will change as the vertical velocity is affected by acceleration / deceleration (and time)
--
The correct calculation is: 170/34 = 5

Am i correct?
 
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