Understanding PV Diagrams - Work

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SUMMARY

The discussion focuses on calculating the work done by a gas during a thermodynamic process represented by a PV diagram, specifically from states 1 to 3 to 6. The correct formula for work is identified as W = PV ln(V2/V1), with the user initially attempting to use W = 3Po * V * ln(3Vo/Vo). The user resolves their confusion regarding the multiplicative factor and confirms that they have solved the problem successfully.

PREREQUISITES
  • Understanding of thermodynamic processes and PV diagrams
  • Familiarity with the ideal gas law and related equations
  • Knowledge of calculus, specifically integration
  • Basic concepts of work in thermodynamics
NEXT STEPS
  • Study the derivation of the work done in isothermal processes using W = nRT ln(V2/V1)
  • Explore different types of thermodynamic processes (isothermal, adiabatic, etc.)
  • Learn about the applications of PV diagrams in real-world thermodynamic systems
  • Investigate the role of the ideal gas law in calculating work and energy changes
USEFUL FOR

This discussion is beneficial for students studying thermodynamics, physics enthusiasts, and professionals in engineering fields who require a solid understanding of gas behavior and work calculations in thermodynamic processes.

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Homework Statement



Calculate the work done by the gas during process 1-> 3-> 6.
Express your answer in terms of Po and Vo.


Homework Equations



W=integral(pv) from V1-V2
W=PVln(V2/V1)

The Attempt at a Solution



3Po*V*ln(3Vo/Vo)

I'm not sure what I'm doing wrong, it keeps telling me I'm off by a multiplicative factor.. Should I be using W=nRT ln(V2/V1) ?
ht tp://i33.photobucket.com/albums/d53/tizzful/151890.jpg (take out the space)
 
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Never mind, I solved it
 

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