Understanding Reactive Power Flow in Power Factor Correction

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SUMMARY

Reactive power (Q) flows between a capacitor and an inductive load when connected in parallel, minimizing the reactive power supplied by the generator. The generator provides leading reactive power to the capacitor and lagging reactive power to the inductive load, resulting in a net reduction of reactive power supplied by the generator. When only a capacitor is connected to the generator, reactive power flows between them, but the presence of the inductive load alters this dynamic, preventing reactive power from flowing back to the generator.

PREREQUISITES
  • Understanding of reactive power in AC circuits
  • Knowledge of power factor correction techniques
  • Familiarity with inductive and capacitive loads
  • Basic principles of electrical generators
NEXT STEPS
  • Research the principles of power factor correction using capacitors
  • Learn about the effects of inductive loads on reactive power flow
  • Study the relationship between leading and lagging reactive power
  • Explore advanced concepts in AC circuit analysis
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Electrical engineers, power system analysts, and anyone involved in optimizing power factor and reactive power management in electrical systems.

QwertyXP
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When you connect a capacitor across an inductive load, reactive power (Q) flows back and forth between capacitor and inductor, so (ideally) the generator doesn't need to supply Q to the load.

My question is, why doesn't the capacitor supply Q to the generator as well? If only a capacitor were connected across a generator, Q would flow from capacitor->generator and vice versa. But when an inductive load is also connected in parallel, Q flows only b/w cap. and ind. and does not go towards the generator. Why is this so?
 
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The generator supplies the capacitor with reactive power (leading), and it supplies the inductive load with lagging reactive power. There is some cancelling of the leading with the lagging, so the generator ends up supplying less reactive power than when supplying the inductive load alone.
 
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Got it, thank you.
 

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