Understanding Relativistic Kinematics for Proton-Photon Collisions

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 3K views
jdstokes
Messages
520
Reaction score
1
Hi all,

I would be very grateful if anyone would be willing to check my understanding of this stuff as it has been several years since I used it in undergrad calculations.

If a proton and a photon collide head-on with known energies, then the energy in the center of mass frame will be given by the invariant mass [itex]E_\mathrm{com} = W[/itex]. Thus [itex]E_\mathrm{com} = \sqrt{(E_\gamma+ E_p)^2-(p_\gamma + p_p)^2} = \sqrt{(E_\gamma+ E_p)^2-\left(E_\gamma + \sqrt{E_p^2 - m_p^2}\right)^2}[/itex].

Does this sound reasonable?
 
Physics news on Phys.org
sure why not, remember that you should have vector p's in the first expression:

[tex]E_\mathrm{com} = \sqrt{(E_\gamma+ E_p)^2-(\vec{p}_\gamma + \vec{p}_p)^2}[/tex]

Just for completeness, then use the fact that they are 'head on'
 
That means you need a minus sign in your last term.