- #1
Pengwuino
Gold Member
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The question I'm given is:
Newton's second law is given by \mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\rightharpoonup$}} <br /> \over F} = \frac{{d\vec p}}{{dt}}. If the force is always parallel to the velocity, show that \mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\rightharpoonup$}} <br /> \over F} = \gamma ^3 m\mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\rightharpoonup$}} <br /> \over a}.
Now, how do I get started on this thing?
Also, what I'm really wondering is how this is actually applied. When they say \mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\rightharpoonup$}} <br /> \over F} = \gamma ^3 m\mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\rightharpoonup$}} <br /> \over a}… what gamma is being used? Also, are we looking at the change in momentum from wrt to the K frame?
Newton's second law is given by \mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\rightharpoonup$}} <br /> \over F} = \frac{{d\vec p}}{{dt}}. If the force is always parallel to the velocity, show that \mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\rightharpoonup$}} <br /> \over F} = \gamma ^3 m\mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\rightharpoonup$}} <br /> \over a}.
Now, how do I get started on this thing?
Also, what I'm really wondering is how this is actually applied. When they say \mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\rightharpoonup$}} <br /> \over F} = \gamma ^3 m\mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\rightharpoonup$}} <br /> \over a}… what gamma is being used? Also, are we looking at the change in momentum from wrt to the K frame?