Understanding Renormalisation Calculations in Field Theory

  • Thread starter Thread starter latentcorpse
  • Start date Start date
  • Tags Tags
    Calculations
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
4 replies · 2K views
latentcorpse
Messages
1,411
Reaction score
0
On p 51 of these notes:
http://www.damtp.cam.ac.uk/user/ho/Notes.pdf ,

I'm trying to follow the calculation [itex]\int \frac{d^dk}{(2 \pi )^d} \frac{1}{(k^2+m^2)^2}= - \frac{\partial}{\partial m^2} \dots[/itex]

It looks to me like we can just use the calculation above and then take the derivative at the end but somehow this isn't working as whilst he has lowered the power on the m^2, he hasn't multiplied through by the old power. Additionally, the argument of the Gamma function has changed!

What's going on?
 
Last edited by a moderator:
Physics news on Phys.org
Have you tried computing the ratio of your result to his?
 
fzero said:
Have you tried computing the ratio of your result to his?

You mean that if I expand out the gamma function in both expressions, I should find they are the same?

Even so though, how did he end up with his version rather than mine?
 
He just used an identity to tidy up the result a bit.
 
fzero said:
He just used an identity to tidy up the result a bit.

So he does it my way then uses [itex]\Gamma(\alpha+1)= \alpha \Gamma(\alpha)[/itex]?