Understanding Rolle's Theorem: Continuity & Differentiability

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Discussion Overview

The discussion centers on the conditions of Rolle's Theorem, specifically the necessity of stating that a function must be continuous on a closed interval and differentiable on an open interval. Participants explore the implications of differentiability on the endpoints of the interval.

Discussion Character

  • Conceptual clarification, Debate/contested

Main Points Raised

  • Omri questions the need for continuity on [a, b] and differentiability on (a, b), suggesting that stating f is differentiable on [a, b] could suffice.
  • One participant argues that if f were stated to be differentiable on [a, b], the theorem would still hold but would be less useful, as it would exclude cases where f is not differentiable at the endpoints.
  • Examples are provided, such as f(x) = √(1 - x²), which is continuous on [-1, 1] and differentiable on (-1, 1) but not differentiable at the endpoints.
  • Another example, f(x) = |1 - x²|, is also continuous on [-1, 1] and differentiable on (-1, 1) but fails to be differentiable at the endpoints.
  • A participant suggests that a possible definition of "differentiable on [-1, 1]" could involve requiring only one-sided derivatives at the endpoints.

Areas of Agreement / Disagreement

Participants express differing views on the necessity of differentiability on the closed interval, with some supporting the original conditions of Rolle's Theorem while others propose alternative interpretations.

Contextual Notes

The discussion highlights the nuances of differentiability at endpoints and the implications for applying Rolle's Theorem, but does not resolve the debate over the definitions and conditions presented.

omri3012
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Hallo.
If we consider Rolle's Theorem:
"If f is continuous on [a, b], differentiable in
(a,b), and f (a) = f (b), then there exists a point c in (a, b) where f'(c) = 0."

Why do we need to state continuity of f in interval and differentiability of f in open segment? Why can't we say f differentiable on [a,b]?

Thanks,

Omri
 
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If you said f is differentiable on [a,b], the result would still be true, just slightly less useful. As stated the theorem shows that the result is true even if f is not differentiable at a or b. If it was restated to require f to be differentiable on [a,b], it could not be used in these cases.
 
for example... [itex]f(x) = \sqrt{(1-x^2)}[/itex] is continuous on [itex][-1,1][/itex] and differentiable on [itex](-1,1)[/itex] but not differentiable on [itex][-1,1][/itex].
 
Similarly, f(x)= |1- x^2| is continuous on [-1, 1], differentiable on (-1, 1) but not differentiable on [-1, 1].
 
HallsofIvy said:
Similarly, f(x)= |1- x^2| is continuous on [-1, 1], differentiable on (-1, 1) but not differentiable on [-1, 1].

A possible definition of "differentiable on [-1,1]" requires only one-sided derivatives at the two endpoints.
 

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