Understanding Sets and Intervals: Proving Complements and Open/Closed Status

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SUMMARY

This discussion focuses on proving two fundamental concepts in set theory related to open and closed sets in real analysis. It establishes that the complement of an open set is indeed a closed set and clarifies that an open interval is classified as an open set while a closed interval is classified as a closed set. The definitions provided for open and closed sets are crucial for understanding these properties, particularly the convergence of sequences within these sets.

PREREQUISITES
  • Understanding of real analysis concepts, specifically open and closed sets.
  • Familiarity with sequences and their convergence in the context of real numbers.
  • Knowledge of set operations, particularly complements.
  • Basic calculus principles related to limits and continuity.
NEXT STEPS
  • Study the definitions and properties of open and closed sets in more depth.
  • Learn about the topology of real numbers and its implications for set theory.
  • Explore examples of open and closed intervals and their complements.
  • Investigate the role of sequences in proving properties of sets in real analysis.
USEFUL FOR

Students in calculus or real analysis courses, educators teaching set theory concepts, and anyone interested in the foundational principles of mathematical analysis.

bonildo
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Homework Statement


Hello, I'm not sure if it's the right place to post this exercise, but I'm learning it in a calculus course.

I need to prove that:

a) The complement of an open set is a closed.
b) An open interval is a open set, a closed interval is a closed set.

Homework Equations


I have the following definitions:

1) An subset A⊂R is open if for all sequence {an}n∈N that converges for l∈A,
∃n0 such that ∀n>n0 ,an∈A.

2) An subset A⊂R is closed if for all sequence {an}n∈N that converges for l∈R,
l∈A.

The Attempt at a Solution



I don't have any ideia how to do it , I never worked on this kind of exercise before
 
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bonildo said:
2) An subset A⊂R is closed if for all sequence {an}n∈N that converges for l∈R,
l∈A.
That's not quite right. You need the constraint that the an are elements of A.
Start with an open set A and consider its complement B = R-A. Let bn be a sequence in B converging to l in R. Consider the consequences of l not being in B. If it's not in B, where is it?
 

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